Square HDU 1518 搜索 题意 原题链接 给你一定若干个木棒,让你使用它们组成一个四边形,要求这些木棒必须全部使用. 解题思路 木棒有多种组合方式,使用搜索来进行寻找,这里需要进行优化,不然复杂度非常高. 因为M最大为20,所以,如果用DFS还是可以接受的. 由所有火柴棒的长度和,我们可以求出要组成正方形的边长.我们设边长为len.在搜索前,首先可以把边长为分数的,也就是火柴棒的长度和不能被4整除的,排除掉. 问题可以转化为从M个数中挑出4组和为len的数. 首先,从M个数中搜索出和…

本题来自:http://acm.hdu.edu.cn/showproblem.php?pid=1518 题意:输入几个长度,判断能否拼成正方形. 以下部分参考了网友代码,终于ac啦. #include <stdio.h> #include <string.h> #include <stdlib.h> ]; ]; int len,m; int comp ( const void *a, const void *b ){return * ( int * ) a - * (…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1518 题目大意:根据题目所给的几条边,来判断是否能构成正方形,一个很好的深搜应用,注意剪枝,以防超时! #include <iostream> #include <cstdio> #include<algorithm> #include <cstring> using namespace std; ],visit[]; int l,n; int dfs(int…

#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<cmath> using namespace std; ],n,El; ]; int dfs(int k,int pos,int nowlen) { int i,j; if(nowlen==El) { if(k==n) ; else nowlen=,pos=; } for(i=pos…

思路:从第一个数开始搜索,将其和与边长比对,相等则计数+1,计数达到3的时候说明可以组成,因为剩下那条必与边长相等,搜索过程注意剪枝,若某个数已被加入边长则不能重复计算,应将其标记,另外应在每一层递归时进行判断,看是否满足结束条件,以此来优化时间 #include<stdio.h> #include<string.h> int a[25],vis[25]; int con,temp,side,sum,flag,k; //con用来记录边数,temp存放暂时的边长,用来与目标边长比对…

解题思路:sum%4!=0    , max<sum/4 #include<iostream>#include<cstdio>#include<cstring>#include<string>#include<algorithm>usingnamespace std;int a[100];bool vis[100],flag;int m,ave;bool dfs(int ans,int sum,int cnt){     if(sum==a…

Problem Description Given a set of sticks of various lengths, is it possible to join them end-to-end to form a square?   Input The first line of input contains N, the number of test cases. Each test case begins with an integer 4 <= M <= 20, the numb…

Given a set of sticks of various lengths, is it possible to join them end-to-end to form a square? Input The first line of input contains N, the number of test cases. Each test case begins with an integer 4 <= M <= 20, the number of sticks. M intege…

题目链接 题目大意: 题意就是输入棍子的数量和每根棍子的长度,看能不能拼成正方形. #include <bits/stdc++.h> using namespace std; int n,m,sum,cur; ],vis[]; bool fp; bool mycmp(int a,int b){ return a>b; } void dfs(int s,int len,int num){ //当前位置,目前长度,成功条数 ){ fp=true;return; } ,,num+); //如果…

Problem Description Given a set of sticks of various lengths, is it possible to join them end-to-end to form a square? Input The first line of input contains N, the number of test cases. Each test case begins with an integer 4 <= M <= 20, the number…