POJ1014 Dividing】的更多相关文章

题目来源:http://poj.org/problem?id=1014 题目大意: Marsha和Bill拥有一些弹珠.但是这些弹珠的价值不一样.每个弹珠的价值都是1到6之间的自然数.他们希望把这些弹珠分为两份,每份的总价值相等.然而,有时候是不存在这样的划分的(即使总的价值为偶数).比如弹珠的价值分别为1,3,4,4.写一个程序判断一些弹珠是否可以被分为价值相等的两份. 输入:每行代表一个测试用例,含6个非负整数.n1,...n6.ni表示价值为i的弹珠有多少个.测试用例最多20000个.输入…
Dividing Time Limit: 1000MS Memory Limit: 10000K Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbles. This would be easy if all the marbles had…
转载请注明出处:http://blog.csdn.net/u012860063 题目链接:id=1014">http://poj.org/problem?id=1014 Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbles. Th…
http://poj.org/problem?id=1014 Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbles. This would be easy if all the marbles had the same value, b…
#include <cstdio> #include <algorithm> #include <cstring> using namespace std; int T,A[10]; bool f[100010]; inline int read(){ int x=0,f=1;char ch=getchar(); while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();} while(ch>='0'&…
Problem Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbles. This would be easy if all the marbles had the same value, because then they could…
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http://poj.org/problem?id=1014 (题目链接) 题意 给出有分别价值为1,2,3,4,5,6的6种物品,输入6个数字,表示相应价值的物品的数量,问一下能不能将物品分成两份,是两份的总价值相等. solution 多年以前写的程序了,现在才写博客= =.这道题一看就是多重背包,所以我们用二进制把它拆分成01背包就很好做了,不知道的话就看<背包九讲>吧.. 首先我们把6种物品的总价值记为S,如果S%2==1,那么显然是无解的.考虑S%2==0的情况.我们把每个种物品用二…
Dividing Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 63013   Accepted: 16315 Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbl…
有价值为1~6的宝物各num[i]个,求能否分成价值相等的两部分. #include <iostream> #include <cstring> #include <string> #include <cstdio> #include <cmath> #include <algorithm> #include <vector> #include <queue> #include <map> #def…