1- 问题描述 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the m…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

class MinStack { public: void push(int x) { if(values.empty()) { values.push_back(x); min_indices.push_back(); } else { if( x < values[min_indices.back()] ) min_indices.push_back(values.size()); values.push_back(x); } } void pop() { values.pop_back()…

原标题:https://oj.leetcode.com/problems/min-stack/ Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the…

这是悦乐书的第177次更新,第179篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第36题(顺位题号是155).设计一个支持push,pop,top和在恒定时间内检索最小元素的堆栈. push(x) - 将元素x推入堆栈. pop() - 删除堆栈顶部的元素. top() - 获取顶部元素. getMin() - 检索堆栈中的最小元素. 例如: MinStack minStack = new MinStack(); minStack.push(-2); minSta…

LeetCode 155:最小栈 Min Stack 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. pu…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the min…

155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } void push(int x) { if(s1.empty() && s2.empty()){ s1.push(x); s2.push(x); } else{ if(x < s2.top()){ s1.push(x); s2.push(x); } else{ s1.push(x); s2…

Min Stack My Submissions Question Solution Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top…