/* HDU4572 Bottles Arrangement http://acm.hdu.edu.cn/showproblem.php?pid=4572 数论 找规律 题意:有m行n列和1-n的数各n个,将其填在m×n的格子里 要求同一列中的数各不相同,同一行中相邻两数的差的绝对值不超过1. 求每一行中值的和的最小值. 这道题很神奇,比赛的时候yy了一发交了上去,没想到真的A了 赛后看题解,发现大家各种yy,然而没有人和我的yy一样, 也许我脑洞过于新奇吧23333 首先这个值肯定比n*m要小…

题目 //找规律,123321123321123321…发现这样排列恰好可以错开 // 其中注意题中数据范围: M是行,N是列,3 <= N < 2×M //则猜测:m,m,m-1,m-1,m-2,m-2,……,2,2,1,1求出前m个数字的和就是答案. //发现案例符合(之前的代码第二天发现案例都跑不对,真不知道我当时眼睛怎么了) #include <iostream> #include<stdio.h> #include<string.h> #inclu…

这题当时竟然没看啊…… 找规律:求和m+m+m-1+m-1+……前n项 ;}…

具体的证明:点击打开链接 我的想法: 要想保证题目所说 构造最小行的和,仅仅能是这样的情况 .....      m-3  m-2  m-1  m    |   m  m-1  m-2  m-3    . .... 所以Ans 也就是取前N项就可. 又由于 It is guaranteed that N is always odd.  显然构造没问题. #include <cstdio> #include <cstring> #include <iostream> #i…

C. Recycling Bottles time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output It was recycling day in Kekoland. To celebrate it Adil and Bera went to Central Perk where they can take bottles from t…

题目链接:http://codeforces.com/problemset/problem/315/A 题目意思:有n个soda bottles,随后给出这n个soda bottles的信息.已知第 i 个bottle来自品牌ai,你可以用这个品牌 ai 来开所有属于品牌bi 的bottles.注意,other特别用黑色粗体来强调,表明该行的除外,也就是说,假如i = 1(隐含的),ai = 1,bi = 1,这个bottle 1 是不能被打开的.需要找出无论用什么方式都不能打开的bottle的…

C. Recycling Bottles   It was recycling day in Kekoland. To celebrate it Adil and Bera went to Central Perk where they can take bottles from the ground and put them into a recycling bin. We can think Central Perk as coordinate plane. There are n bott…

Suppose you have N integers from 1 to N. We define a beautiful arrangement as an array that is constructed by these N numbers successfully if one of the following is true for the ith position (1 ≤ i ≤ N) in this array: The number at the ith position…

The 11th Zhejiang Provincial Collegiate Programming Contest is coming! As a problem setter, Edward is going to arrange the order of the problems. As we know, the arrangement will have a great effect on the result of the contest. For example, it will…

B - Problem Arrangement Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Submit Status Practice ZOJ 3777 Description The 11th Zhejiang Provincial Collegiate Programming Contest is coming! As a problem setter, Edward is going…