lc 684 Redundant Connection 684 Redundant Connection In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one addi…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

We are given a "tree" in the form of a 2D-array, with distinct values for each node. In the given 2D-array, each element pair [u, v] represents that v is a child of u in the tree. We can remove exactly one redundant pair in this "tree"…

题目: In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two differe…

In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

原题链接在这里:https://leetcode.com/problems/redundant-connection-ii/ 题目: In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 并查集 日期 题目地址:https://leetcode.com/problems/redundant-connection/description/ 题目描述 In this problem, a tree is an undirected graph that is connected and has no cycles. The given i…

https://leetcode.com/problems/redundant-connection/description/ Use map to do Union Find. class Solution { public: vector<int> findRedundantConnection(vector<vector<int>>& edges) { unordered_map<int,int> parent; for (const auto…

Leetcode之并查集专题-684. 冗余连接(Redundant Connection) 在本问题中, 树指的是一个连通且无环的无向图. 输入一个图,该图由一个有着N个节点 (节点值不重复1, 2, ..., N) 的树及一条附加的边构成.附加的边的两个顶点包含在1到N中间,这条附加的边不属于树中已存在的边. 结果图是一个以边组成的二维数组.每一个边的元素是一对[u, v] ,满足 u < v,表示连接顶点u 和v的无向图的边. 返回一条可以删去的边,使得结果图是一个有着N个节点的树.如果有…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

https://leetcode.com/problems/redundant-connection/ 一个无向图,n个顶点有n条边,输出一条可以删除的边,删除后使得图成为一棵树.可以使用并查集解决. class Solution { public: ]; void initfather() { ; i<=; i++) father[i]=i; } int findFather(int x) { if(father[x]!=x) father[x] = findFather(father[x])…

684. 冗余连接 在本问题中, 树指的是一个连通且无环的无向图. 输入一个图,该图由一个有着N个节点 (节点值不重复1, 2, -, N) 的树及一条附加的边构成.附加的边的两个顶点包含在1到N中间,这条附加的边不属于树中已存在的边. 结果图是一个以边组成的二维数组.每一个边的元素是一对[u, v] ,满足 u < v,表示连接顶点u 和v的无向图的边. 返回一条可以删去的边,使得结果图是一个有着N个节点的树.如果有多个答案,则返回二维数组中最后出现的边.答案边 [u, v] 应满足相同的格式…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

冗余连接 在本问题中, 树指的是一个连通且无环的无向图. 输入一个图,该图由一个有着N个节点 (节点值不重复1, 2, ..., N) 的树及一条附加的边构成.附加的边的两个顶点包含在1到N中间,这条附加的边不属于树中已存在的边. 结果图是一个以边组成的二维数组.每一个边的元素是一对[u, v] ,满足 u < v,表示连接顶点u 和v的无向图的边. 返回一条可以删去的边,使得结果图是一个有着N个节点的树.如果有多个答案,则返回二维数组中最后出现的边.答案边 [u, v] 应满足相同的格式 u…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

Union Find算法基础 Union Find算法用于处理集合的合并和查询问题,其定义了两个用于并查集的操作: Find: 确定元素属于哪一个子集,或判断两个元素是否属于同一子集 Union: 将两个子集合并为一个子集 并查集是一种树形的数据结构,其可用数组或unordered_map表示: Find操作即查找元素的root,当两元素root相同时判定他们属于同一个子集:Union操作即通过修改元素的root(或修改parent)合并子集,下面两个图展示了id[6]由6修改为9的变化:   …

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

645. Set Mismatch The set S originally contains numbers from 1 to n. But unfortunately, due to the data error, one of the numbers in the set got duplicated to another number in the set, which results in repetition of one number and loss of another nu…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

目录 二分查找 排序的写法 BFS的写法 DFS的写法 回溯法 树 递归 迭代 前序遍历 中序遍历 后序遍历 构建完全二叉树 并查集 前缀树 图遍历 Dijkstra算法 Floyd-Warshall算法 Bellman-Ford算法 最小生成树 Kruskal算法 Prim算法 拓扑排序 双指针 动态规划 状态搜索 贪心 本文的目的是收集一些典型的题目,记住其写法,理解其思想,即可做到一通百通.欢迎大家提出宝贵意见! 博主有算法题解的微信公众号啦,欢迎关注「负雪明烛」,持续更新算法题的解题思路…

Union Find算法基础 Union Find算法用于处理集合的合并和查询问题,其定义了两个用于并查集的操作: Find: 确定元素属于哪一个子集,或判断两个元素是否属于同一子集 Union: 将两个子集合并为一个子集 并查集是一种树形的数据结构,其可用数组或unordered_map表示: Find操作即查找元素的root,当两元素root相同时判定他们属于同一个子集:Union操作即通过修改元素的root(或修改parent)合并子集,下面两个图展示了id[6]由6修改为9的变化:   …

图基础 图(Graph)应用广泛,程序中可用邻接表和邻接矩阵表示图.依据不同维度,图可以分为有向图/无向图.有权图/无权图.连通图/非连通图.循环图/非循环图,有向图中的顶点具有入度/出度的概念. 面对图相关问题,第一步是将问题转为用图表示(邻接表/邻接矩阵),二是使用图相关算法求解. 相关LeetCode题: 997. Find the Town Judge  题解 1042. Flower Planting With No Adjacent  题解 图的遍历(DFS/BFS) 图的遍历/搜索…

UnionFind就是acm中常用的并查集... 并查集常用操作 另外补充一下STL常用操作 相关问题: 547. Friend Circles 纯裸题噢... class Solution { public: ]; ]; void uf_init(int x) { ;i<=x;i++) root[i]=i; } int uf_find(int x) { if(x!=root[x]) root[x]=uf_find(root[x]); return root[x]; } void uf_unio…

［抄题］: Given a list accounts, each element accounts[i] is a list of strings, where the first element accounts[i][0] is a name, and the rest of the elements are emails representing emails of the account. Now, we would like to merge these accounts. Two…