写省选的题目对noip没什么大用 关键是 细节题或者是思考题比较重要 练思维自然是CF比较好了 把我见到的比较好的CF题放上来刷一刷. LINK:Complete the projects 就是说一个人 初始值为R 有n项工作每项工作有两种属性 a和b 当且仅当 R>=a时可以完成这项任务 且R+=b; 每项任务只能完成一次 问能否把所有工作完成.注:b可能为负. 怎么做?显然对于b>=0的工作我们按照a由小到大的顺序直接做如果有不能完成的任务的话 那便一定不能完成.考虑如何做负值的工作? 想…

three version are provided. disjoint set, linked list version with weighted-union heuristic, rooted tree version with rank by union and path compression, and a minor but substantial optimization for path compression version FindSet to avoid redundanc…

转自:http://www.wowotech.net/linux_kenrel/dt_basic_concept.html 一.前言 一些背景知识(例如:为何要引入Device Tree,这个机制是用来解决什么问题的)请参考引入Device Tree的原因,本文主要是介绍Device Tree的基础概念. 简单的说,如果要使用Device Tree,首先用户要了解自己的硬件配置和系统运行参数,并把这些信息组织成Device Tree source file.通过DTC(Device Tree C…

题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=3333 Description After inventing Turing Tree, 3xian always felt boring when solving problems about intervals, because Turing Tree could easily have the solution. As well, wily 3xian made lots of new…

传送门 Description A binary tree is a finite set of vertices that is either empty or consists of a root r and two disjoint binary trees called the left and right subtrees. There are three most important ways in which the vertices of a binary tree can be…

$.extend($.fn.tree.methods, { highlight: function(jq, target){ return jq.each(function(){ $(this).find('.tree-node-hover').removeClass('tree-node-hover'); $(target).addClass('tree-node-hover'); }) }, nav: function(jq){ return jq.each(function(){ var…

Color a Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 828    Accepted Submission(s): 272 Problem DescriptionBob is very interested in the data structure of a tree. A tree is a directed gr…

Hardwood Species Time Limit: 10000MS Memory Limit: 65536K Total Submissions: 20619 Accepted: 8083 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter. America's…

一棵树,边长都是1,问这棵树有多少点对的距离刚好为k 令tree(i)表示以i为根的子树 dp[i][j][1]:在tree(i)中,经过节点i,长度为j,其中一个端点为i的路径的个数dp[i][j][0]:在tree(i)中,经过节点i,长度为j,端点不在i的路径的个数 则目标:∑(dp[i][k][0]+dp[i][k][1])初始化:dp[i][0][1]=1,其余为0 siz[i]:tree(i)中,i与离i最远的点的距离递推:dp[i][j][0]+=dp[i][j-l][1]*dp[…

/* Dynamic tree generation and placement in a night-time scene Demonstrates: How to create a height map and splat map from scratch to use for realistic terrain How to use fratacl algorithms to create a custom tree-generating geometry primitive How to…