做$n$次递推求出$n$维Hash值即可,时间复杂度$O(nk)$. #include<cstdio> #define N 500010 int n,i,j,t,delta,ca,cb,a[10],b[10],c[N],d[N],p[N][10]; int seed[10]={233,13331,997,733,811,953,2011,1999,1997,1801}; unsigned int pow,target,f[11][N]; inline void read(int&a){…
题目 Given an input string(s) and a pattern(p), implement regular expression matching with support for '.' and ''.   '.' Matches any single character.   '' Matches zero or more of the preceding element. The matching should cover the entire input string…
Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (n…
Given an input string (s) and a pattern (p), implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the enti…
Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…
问题描述:Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype shou…
这个题目要求在一个大矩阵里面匹配一个小矩阵,是AC自动机的灵活应用 思路是逐行按普通AC自动机匹配,用过counts[i][j]记录一下T字符矩阵以i行j列为开头的与P等大的矩阵区域 有多少行已经匹配了,显然如果该数值==p的行数,则说明匹配成功 就是在自动机的过程中,匹配得时候要稍微多想一下,每次匹配都要调用函数对 counts进行维护,以及还要注意某些行是相同的情况,用个链表保存,匹配成功后直接链过去继续对counts进行维护 最后统计counts里面有多少个值==p的行数即可得出结果 #i…
网址:https://leetcode.com/problems/camelcase-matching/ 依题意可得逻辑 class Solution { public: vector<bool> camelMatch(vector<string>& queries, string pattern) { vector<bool> ans; ; ; // didn't pushed for(string s : queries) { i = ; flag = ;…
搬运工了- - https://blog.csdn.net/jmspan/article/details/51460021…
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