【Floyd(并非水题orz)】BZOJ4093-[Usaco2013 Dec]Vacation Planning

【【Floyd(并非水题orz)】BZOJ4093-[Usaco2013 Dec]Vacation Planning】的更多相关文章

【Floyd(并非水题orz)】BZOJ4093-[Usaco2013 Dec]Vacation Planning

最近刷水太多标注一下防止它淹没在silver的水题中……我成为了本题,第一个T掉的人QAQ [题目大意] Bovinia设计了连接N (1 < = N < = 20,000)个农场的航班.对于任何航班,指定了其中的k个农场作为枢纽. (1 < = K <= 200 , K < = N). 目前,共有M种单向航班( 1 < = M < = 20,000 ),第i个航班从农场u_i至农场v_i花费d_i ( 1 < = d_i < =10,000 )美元.…

bzoj 4097: [Usaco2013 dec]Vacation Planning

4097: [Usaco2013 dec]Vacation Planning Description Air Bovinia is planning to connect the N farms (1 <= N <= 200) that the cows live on. As with any airline, K of these farms (1 <= K <= 100, K <= N) have been selected as hubs. The farms are…

bzoj4097 [Usaco2013 dec]Vacation Planning

Description Air Bovinia is planning to connect the N farms (1 <= N <= 200) that the cows live on. As with any airline, K of these farms (1 <= K <= 100, K <= N) have been selected as hubs. The farms are conveniently numbered 1..N, with farms…

[Usaco2013 DEC] Vacation Planning

[题目链接] https://www.lydsy.com/JudgeOnline/problem.php?id=4093 [算法] 对于k个枢纽 , 分别在正向图和反向图上跑dijkstra最短路 , 即可时间复杂度 : O(K(N + M) log N) [代码] #include<bits/stdc++.h> using namespace std; #define MAXN 20010 #define MAXK 210 typedef long long LL; const LL in…

没讲明白的水题orz

有一道解释程序的水题没给非计算机专业的同学讲明白orz,在这里再练一下.. 源代码完全没有缩进真是难以忍受.. p.s.懂递归就不用看了#include <stdio.h> int n = 0; int rest[7][7]; void swap(int *a, int *b) { int m; m = *a; *a = *b; *b = m; } void perm(int list[], int k, int m) { int i; int j; if(k > m) { for (i…

变形课 HDU - 1181 【floyd传递闭包水题】

呃......变形课上Harry碰到了一点小麻烦,因为他并不像Hermione那样能够记住所有的咒语而随意的将一个棒球变成刺猬什么的,但是他发现了变形咒语的一个统一规律:如果咒语是以a开头b结尾的一个单词,那么它的作用就恰好是使A物体变成B物体.Harry已经将他所会的所有咒语都列成了一个表,他想让你帮忙计算一下他是否能完成老师的作业,将一个B(ball)变成一个M(Mouse),你知道,如果他自己不能完成的话,他就只好向Hermione请教,并且被迫听一大堆好好学习的道理. Input测试数据…