https://nanti.jisuanke.com/t/30991 题意 一个n*m的方格矩阵,有的格子被涂成了黑色,问该矩阵中有多少个子矩阵,子矩阵不包含黑色格子. 分析 参考https://blog.csdn.net/Sirius_han/article/details/82313029 n=1e5,m=100.首先思考一下没有黑点的话,子矩阵总数怎么算. 现有长为L的大矩阵,对于固定高度h,其子矩阵的个数是这样计算的 ; i<=L; i++){ ; j--){ count+=h; } }…

题目链接:https://nanti.jisuanke.com/t/30991 2000ms 262144K   Feeling hungry, a cute hamster decides to order some take-away food (like fried chicken for only 3030 Yuan). However, his owner CXY thinks that take-away food is unhealthy and expensive. So she…

题意:一个n*m的方格矩阵,有的格子被涂成了黑色,问该矩阵中有多少个子矩阵,子矩阵不包含黑色格子; 思路:对于一个长为L, 高为H的无黑点矩阵中包含的高为H的子矩阵个数为L+(L-1)+(L-2)+...+1个:这是直接算的一种方法:如何程序表示该计算呢? ; i<=L; i++){ ; j--){ count+=; } } 这样的一个双层循环就表示了上式:那么所有子矩阵个数就是三层循环,高由1->H: ; h<=H; h++){ ; i<=L; i++){ ; j--){ cou…

A square-free integer is an integer which is indivisible by any square number except 11. For example, 6 = 2 \cdot 36=2⋅3 is square-free, but 12 = 2^2 \cdot 312=22⋅3 is not, because 2^222 is a square number. Some integers could be decomposed into prod…

ACM-ICPC 2018 南京赛区网络预赛 E题 题目链接: https://nanti.jisuanke.com/t/30994 Dlsj is competing in a contest with n (0 < n \le 20)n(0<n≤20) problems. And he knows the answer of all of these problems. However, he can submit ii-th problem if and only if he has s…

题目链接:https://nanti.jisuanke.com/t/30991 Feeling hungry, a cute hamster decides to order some take-away food (like fried chicken for only 3030 Yuan). However, his owner CXY thinks that take-away food is unhealthy and expensive. So she demands her hams…

J. Sum 26.87% 1000ms 512000K   A square-free integer is an integer which is indivisible by any square number except 11. For example, 6 = 2 \cdot 36=2⋅3 is square-free, but 12 = 2^2 \cdot 312=22⋅3 is not, because 2^222 is a square number. Some integer…

G. Lpl and Energy-saving Lamps 42.07% 1000ms 65536K   During tea-drinking, princess, amongst other things, asked why has such a good-natured and cute Dragon imprisoned Lpl in the Castle? Dragon smiled enigmatically and answered that it is a big secre…

A. An Olympian Math Problem 54.28% 1000ms 65536K   Alice, a student of grade 66, is thinking about an Olympian Math problem, but she feels so despair that she cries. And her classmate, Bob, has no idea about the problem. Thus he wants you to help him…

轻轻松松也能拿到区域赛名额,CCPC真的好难 An Olympian Math Problem 问答 只看题面 54.76% 1000ms 65536K   Alice, a student of grade 66, is thinking about an Olympian Math problem, but she feels so despair that she cries. And her classmate, Bob, has no idea about the problem. T…

262144K   There are NN cities in the country, and MM directional roads from uu to v(1\le u, v\le n)v(1≤u,v≤n). Every road has a distance c_ici​. Haze is a Magical Girl that lives in City 11, she can choose no more than KK roads and make their distanc…

ACM-ICPC 2018 南京赛区网络预赛 A. An Olympian Math Problem 计算\(\sum_{i=1}^{n-1}i\cdot i!(MOD\ n)\) \(\sum_{i=1}^{n-1}i\cdot i! = \sum_{i=1}^{n-1}[(i+1)!-i!](MOD\ n)=n!-1!(MOD\ n)=n-1\) #include<bits/stdc++.h> using namespace std; int T; long long n; int mai…

题目链接:https://nanti.jisuanke.com/t/30999 参考自博客:https://kuangbin.github.io/2018/09/01/2018-ACM-ICPC-Nanjing-online-J/ 题目中文: 1000毫秒 512000K 无方形整数是一个整数,除了1以外的任何平方数都不可分 这个数.例如,6 = 2 *3,6=2*3,6是无方形整数,但12 = 2 ^ 2*3,,因为2 ^ 2是正方形数.有些整数可以分解为两个无方形整数的乘积,可能有多种分解方…

A  签到题 Alice, a student of grade 666, is thinking about an Olympian Math problem, but she feels so despair that she cries. And her classmate, Bob, has no idea about the problem. Thus he wants you to help him. The problem is: We denote k!k!k!: k!=1×2×…

题目链接:https://nanti.jisuanke.com/t/31001 题目大意:给出一个含有n个点m条边的带权有向图,求1号顶点到n号顶点的最短路,可以使<=k条任意边的权值变为0. 样例输入 复制 1 5 6 1 1 2 2 1 3 4 2 4 3 3 4 1 3 5 6 4 5 2 样例输出 复制 3 解题思路:可以用两种做法,不过都差不多,应该算是同一种思路的不同写法.第一种是在建图时,将一个点拆成k个层次的点,应该总共有k+1层,每个相同层次的点按输入的边权连接,每个点可以向它…

题目链接:https://nanti.jisuanke.com/t/30996 中文题目: 在喝茶的过程中,公主,除其他外,问为什么这样一个善良可爱的龙在城堡里被监禁Lpl?龙神秘地笑了笑,回答说这是个大秘密.暂停后,龙补充道: - 我们有合同.租赁协议.他总是一整天都在工作.他喜欢沉默.除此之外,住在城堡还有更多的优势.比如说,很容易证明未接来电的合理性:电话铃声无法从手机离开的城堡的另一侧到达.因此,监禁只是一个故事.实际上,他思考一切.他很聪明.例如,他开始用整个城堡中的节能灯替换白炽灯.…

https://nanti.jisuanke.com/t/30998 题意 给一串由0..9组成的数字字符串,求所有不同回文串的权值和.比如说“1121”这个串中有“1”,“2”,“11”,“121”三种回文串,他们的权值分别是1,2,11,121.最终输出ans=135. 分析 第一次知道马拉车是manacher...涨姿势了 在马拉车进行的过程中,进行子回文串的统计去重. 这里的哈希去重方法重点学习理解. #include <iostream> #include <cstdio>…

https://nanti.jisuanke.com/t/30994 题意 给你n个题目,对于每个题目,在做这个题目之前,规定了必须先做哪几个题目,第t个做的题目i得分是t×ai+bi问最终的最大得分是多少? 分析 枚举所有状态,在转移时判断合法性,然后直接转移就好了.dp初始化为-inf,边界值dp[0]=0; #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring&g…

https://nanti.jisuanke.com/t/30992 题意 把m张牌(牌上数字范围是1-13)放到栈里n个人,每个人首次从栈顶取5张牌,轮流取取完牌后,第1个人出他手里最小的牌,然后2-n个人轮流出牌,每次出牌的选择是:(1)出比前一个人的牌大1的牌(2)在前一个牌不是2的时候可以出2(优先选择(1)出牌方式出牌)如果第i个人没有能出的牌,他就“过”如果第X个人出完牌后,走了一圈到了X,中间没一个人能出牌,那么从X开始所有人要从栈中取一张牌,接着,X出他手里最小的牌.如果栈里没牌…

https://nanti.jisuanke.com/t/30999 题意 f(i)表示i能拆分成两个数的乘积,且要求这两个数中各自都没有出现超过1次的质因子的方案数.每次给出n,求∑(n,i=1)f(i) 分析 n到2e7,肯定得打表离线做. 类似打欧拉函数表的方式,对于数d以及素数p,f(p)=2:当d|p时,若d|p^2,则f(d∗p)=0:否则f(d∗p)=f(d)/2;当d†p时,f(d∗p)=f(d)∗2 #include<bits/stdc++.h> using namespac…

https://nanti.jisuanke.com/t/30996 题意 每天增加m个灯泡,n个房间,能一次性换就换,模拟换灯泡过程.询问第几天的状态 分析 离线做,按题意模拟.比赛时线段树写挫了..导致不断超时,我太弱了.每次询问符合要求的最左边的点. #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <string> #i…

<题目链接> 题目大意: 有N个城市,这些城市之间有M条有向边,每条边有权值,能够选择K条边 边权置为0,求1到N的最短距离. 解题分析: 分层图最短路模板题,将该图看成 K+1 层图,然后具体解析见代码: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #include <queue> using namespace std;…

A. An Olympian Math Problem cout << n - 1 << endl; #include <bits/stdc++.h> using namespace std; #define ll long long int t; ll n; inline void Run() { scanf("%d", &t); while (t--) { scanf("%lld", &n); printf()…

题目来源:https://nanti.jisuanke.com/t/A1956 题意:找一个数拆成无平方因子的组合数,然后求前缀和. 解题思路:我们可以把某个数分解质因数,如果某个数可以分解出三个相同的质数那么该f(n)=0,比如8=2*2*2,  24=2*2*2*3,所以f(8)=f(24)=0:如果该数是素数那么f(n)=2:并且我们可以发现,如果m,n互质,那么f(n*m)=f(n)*f(m): #include<iostream> #include<cstring> #i…

题目链接: https://nanti.jisuanke.com/t/31001 超时代码: #include<bits/stdc++.h> using namespace std; # define maxn 10000000+10 # define inf 0x3f3f3f3f int n,m,k; int num; int head[maxn]; int dis[maxn]; int vis[maxn]; struct node { int ne; int to; int co; } q…

https://www.jisuanke.com/contest/1555?view=challenges 题意: 题解:写完都没发现是个积性函数233 想法就是对x分解质因数,f(x)就是2^k,其中k是x分解结果中次数为一的质因子个数.如果有某个次数大于等于3,f(x)==0; 这样明显会TLE 所以就想一个递推的方法. 于是魔改了一下线性筛. #include<iostream> #include<cstdlib> #include<cstdio> #includ…

题意:求本质不同的回文子串的和 题解:先构造pam,然后根据pam的原理(ch表示在该节点表示的回文串两侧加上该字符)对于每个节点维护一个表示该节点字符串的值,加起来即可 //#pragma GCC optimize(2) //#pragma GCC optimize(3) //#pragma GCC optimize(4) //#pragma GCC optimize("unroll-loops") //#pragma comment(linker, "/stack:200…

During tea-drinking, princess, amongst other things, asked why has such a good-natured and cute Dragon imprisoned Lpl in the Castle? Dragon smiled enigmatically and answered that it is a big secret. After a pause, Dragon added: — We have a contract.…

There are N cities in the country, and M directional roads from u to v(1≤u,v≤n). Every road has a distance ci. Haze is a Magical Girl that lives in City 1, she can choose no more than K roads and make their distances become 0. Now she wants to go to…

类似题解 There are NN cities in the country, and MM directional roads from uu to v(1\le u, v\le n)v(1≤u,v≤n). Every road has a distance c_ici​. Haze is a Magical Girl that lives in City 11, she can choose no more than KK roads and make their distances be…