Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…

Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "-zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd-.". Now we have another string p. Your job is to find out…

Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/unique-substrings-in-wraparound-string/description/ 题目描述: Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so…

详见:https://leetcode.com/problems/unique-substrings-in-wraparound-string/description/ C++: class Solution { public: int findSubstringInWraproundString(string p) { vector<int> cnt(26, 0); int len = 0; for (int i = 0; i < p.size(); ++i) { if (i >…

Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…

Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…

Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this: "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....". Now we have another string p. Your job is to find…

2018-09-01 22:50:59 问题描述: 问题求解: 如果单纯的遍历判断,那么如何去重保证unique是一个很困难的事情,事实上最初我就困在了这个点上. 后来发现是一个动态规划的问题,可以将每个字符结尾的最长长度进行保存,这样就巧妙的解决的重复的问题. The max number of unique substring ends with a letter equals to the length of max contiguous substring ends with that…

467. Unique Substrings in Wraparound String Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Note…

[题目]F. Substrings in a String [题意]给定小写字母字符串s,支持两种操作:1.修改某个位置的字符,2.给定字符串y,查询区间[l,r]内出现y多少次.|s|,Σ|y|<=10^5,time=6s. [算法]Bitset [题解]假设S的长度为n,那么对每个字符建一个长度为n的bitset,1表示该位置为该字符,修改时直接修改. 查询的时候将字符串y所有的字符的bitset,按顺序错位and,这样最后得到1表示y为子串,count一下即可. 复杂度O(n^2/32),…

Description Find the first unique character in a given string. You can assume that there is at least one unique character in the string. Example For "abaccdeff", return 'b'. 解题:返回仅出现一次,并且排在最前面的那个元素,而不是返回第一个不同的元素,一开始理解错了.如果仅仅对于ASCII中的256个字符,可以用数组…

387. First Unique Character in a String Easy Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: You…

1.1 Implement an algorithm to determine if a string has all unique characters. What if you cannot use additional data structure? 这道题让我们判断一个字符串中是否有重复的字符,要求不用特殊的数据结构,这里应该是指哈希表之类的不让用.像普通的整型数组应该还是能用的,这道题的小技巧就是用整型数组来代替哈希表,在之前Bitwise AND of Numbers Range 数…

转:http://software.techassistbox.com/unique-constraint-on-single-string-column-with-greendao_384521.html I want to make unique constraint on String value with GreenDao. I have following piece of code: Entity category = schema.addEntity('Category'); ca…

问题描述 Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Java算法实现 public class Solution { public int first…

题目标签:String, HashMap 题目给了我们一个 string,让我们找出 第一个 唯一的 char. 设立一个 hashmap,把 char 当作 key,char 的index 当作value. 遍历string,如果这个 char 没有在 map 里,说明第一次出现,存入 char,index:                    如果这个 char 已经在 map 里,说明不是第一次出现,而且我们不在乎这种情况,更新 char, -1. 遍历hashmap,把最小的 inde…

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: You may assume the string contain only lowercase…

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. 分析:找出字符串中第一次出现且不重复的字符,返回其字符的下标,如果不存在就返回-1. 用hashMap进行求…

Problem: Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Example: s = "leetcode" return 0. s = "loveleetcode", return 2. 本题的第一想法是开一个字母表计数器,遍历string s中的元素,并利用计数器对每一个字母计…

-------------------------------------------------- 最开始的想法是统计每个字符的出现次数和位置,如下: AC代码: public class Solution { public int firstUniqChar(String s) { Count c[]=new Count[26]; for(int i=0;i<s.length();i++){ int index=s.charAt(i)-'a'; if(c[index]==null) c[in…

原题链接在这里:https://leetcode.com/problems/first-unique-character-in-a-string/ 题目: Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "lovele…

最近公司搬家了,有两天没写了,今天闲下来了,继续开始算法之路. leetcode的题目如下: Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: Y…

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0.   s = "loveleetcode", return 2. Note: You may assume the string contain only lowerca…

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: You may assume the string contain only lowercase…

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: You may assume the string contain only lowercase…

这是悦乐书的第213次更新,第226篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第81题(顺位题号是387).给定一个字符串,找到它中的第一个非重复字符并返回它的索引. 如果它不存在,则返回-1.例如: 输入:"leetcode" 输出:0 输入:"loveleetcode", 输出:2 注意:您可以假设该字符串仅包含小写字母. 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java…

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: You may assume the string contain only lowercase…

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: You may assume the string contain only lowercase…

转:http://stackoverflow.com/questions/22070281/greendao-support-for-unique-constraint-on-multiple-columns Does GreenDao supports unique constraint on multiple columns? Equivalent of the following: create table projects ( _id integer primary key autoin…