FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 20784    Accepted Submission(s): 9220Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster…

FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5546    Accepted Submission(s): 2393Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster i…

#include<stdio.h> #include<string.h> #include<algorithm> #include<set> #include<stack> using namespace std; ; struct point { int w,s,per,id; }p[maxn]; int cmp(point a,point b) { return a.s>b.s; } int dp[maxn]; int main() {…

链接: https://vjudge.net/problem/HDU-1160 题意: FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so th…

动态规划的解决方法是找到动态转移方程. 题目地址:http://acm.hdu.edu.cn/game/entry/problem/show.php?chapterid=3&sectionid=2&problemid=4 题目大意:找到一个最多的老鼠序列,使得序列中的老鼠的体重满足递增,相应老鼠的速度满足递 减.即可要求找出老鼠体重递增,速度递减的最长子序列(不需要连续). 思路:动态转移方程的确定,状态f[i]表示前i个老鼠中的最长递减子序列长度,状态转移方程为mouse[i].len…

/* 弃坑 */ #include<cstdio> #include<algorithm> using namespace std; ,M=N*; ],nxt[N<<],ed,cur,ans[N]; int size[N],f[N],d[N],son[N],top[N]; int fa[N],dep[N],A[N],B[N]; ],V[M],W[M],NXT[M],ED; ]; void add(int x,int y){v[++ed]=y;nxt[ed]=g[x];g…

J. FatMouse's Speed FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are incre…

body,td { font-family: 微软雅黑; font-size: 10pt }   OpenVZ VPS加速方案–Final Speed OpenVZ VPS加速方案–Final Speed 原理猜想 安装和配置 最后说点情怀- 最近我那乞丐版的Bandwagon VPS不知道抽什么疯,慢的要死.换了几个机房都不行. 别说没事儿上个youtobe,连google一下都得老半天打不开. 尝试了下GreenVPN,速度还凑合,正准备要放弃这个VPS的时候,一不小心看到了一篇关于VPS加…

在日常用语中,这两个词没有区别,可以通用. 而在物理学里,velocity 是一个矢量(vector quantity)表示起点与终点间直线距离的长度除以所用时间所得的量,并注明方向;而 speed 是一个数量(scalar quantity),是指起点到终点所走过的所有路程除以所用时间所得的量,且不标明方向.…

FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13194    Accepted Submission(s): 5807Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster i…