（字符串 KMP）Blue Jeans -- POJ -- 3080:

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（字符串 KMP）Blue Jeans -- POJ -- 3080:

链接: http://poj.org/problem?id=3080 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=88230#problem/E (密码0817) Blue Jeans Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14544 Accepted: 6478 Description The Genographic Project is a…

Match:Blue Jeans(POJ 3080)

DNA序列题目大意:给你m串字符串,要你找最长的相同的连续字串这题暴力kmp即可,注意要按字典序排序,同时,是len<3才输出no significant commonalities #include <iostream> #include <functional> #include <algorithm> #include <string.h> #define MAX 60 using namespace std; typedef char* _…

Blue Jeans - POJ 3080（多串的共同子串）

题目大意:有M个串,每个串的长度都是60,查找这M个串的最长公共子串(连续的),长度不能小于3,如果同等长度的有多个输出字典序最小的那个. 分析:因为串不多,而且比较短,所致直接暴力枚举的第一个串的所有子串,比较暴力的做法,如果串的长度大一些就没法玩了. 代码如下: ==================================================================================== #include<stdio.h> #include…

Blue Jeans POJ 3080 寻找多个串的最长相同子串

Description The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated. As an IBM researcher, you have been tas…

Blue Jeans - poj 3080(后缀数组)

大致题意: 给出n个长度为60的DNA基因(A腺嘌呤 G鸟嘌呤 T胸腺嘧啶 C胞嘧啶)序列,求出他们的最长公共子序列使用后缀数组解决 #include<stdio.h> #include<string.h> ],res[]; ],loc[]; ],rank[],height[]; ],wb[],wv[],wd[]; ]; int seq_num; int cmp(int *r,int a,int b,int l){ return r[a]==r[b]&&r[a+l…

POJ 3080 Blue Jeans (求最长公共字符串）

POJ 3080 Blue Jeans (求最长公共字符串) Description The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated. As an IB…