在一个数组中找出两个不同的仅出现一次的数(其他数字出现两次) 同样用亦或来解决(参考编程之美的1.5) 先去取出总亦或值 然后分类,在最后一位出现1的数位上分类成 ans[0]和ans[1] a&(-a)就是计算出这个数,可以参考树状数组. 最后就是注意(nums[i] & a) == 0要加().注意符号运算优先级 class Solution { public: vector<int> singleNumber(vector<int>& nums) {…

LeetCode 260. Single Number III(只出现一次的数字 III)…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. Example: Input: [1,2,1,3,2,5] Output: [3,5] Note: The order of the result is…

Problem: Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: T…

题目描述: Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once.For example:Given nums = [1, 2, 1, 3, 2, 5], return [3, 5].Note:1.The order of…

传送门 Description Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5].…

leetcode 136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解题思路: 如果以线性复杂度和…

136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…

Single Number III Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. Example: Input: [1,2,1,3,2,5] Output: [3,5] Note: The order…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find >the two elements that a…

问题描述: https://leetcode.com/problems/single-number-iii/ 在一个数组里面,只有两个元素仅出现过1次,其余都出现过两次.找出出现仅一次的那两个(a, b). 要求常量空间,线性时间. 问题解决: 这题用到“神奇的位运算”. 1.因为除了特殊的两个元素,其余两两出现,那么就想到了XOR(异或). 2.从头到尾XOR之后,会得到a xor b 的结果.接下来我们试着把这两个元素分离开来. 3.我们在a xor b 中找到任意一位XOR[diff_po…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 异或 字典 日期 题目地址:https://leetcode.com/problems/single-number-iii/description/ 题目描述 Given an array of numbers nums, in which exactly two elements appear only once and all the other…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…

给定一个整数数组 nums,其中恰好有两个元素只出现一次,其他所有元素均出现两次. 找出只出现一次的那两个元素.示例:给定 nums = [1, 2, 1, 3, 2, 5], 返回 [3, 5].注意:    结果的顺序并不重要,对于上面的例子 [5, 3] 也是正确答案.    你的算法应该具有线性复杂度,你能否仅使用恒定的空间复杂度来实现它?详见:https://leetcode.com/problems/single-number-iii/description/ Java实现: cla…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. 代码如下: public cla…

翻译 给定一个整型数组,除了某个元素外其余的均出现了三次. 找出这个元素. 备注: 你的算法应该是线性时间复杂度. 你能够不用额外的空间来实现它吗? 原文 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you…

翻译 给定一个整型数组,除了某个元素外其余元素均出现两次. 找出这个仅仅出现一次的元素. 备注: 你的算法应该是一个线性时间复杂度. 你能够不用额外空间来实现它吗? 原文 Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could yo…

Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Output:…

Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…

136. Single Number 意思就是给你一堆数,每个数都出现了两次,只有一个数只出现了一次,找出这个数 位运算(和c艹一样) &:按位与 |:按位或 ^:异或(一样为0,不一样为1) 再说一下异或的性质,满足交换律和结合律 因此: 对于任意一个数n n ^ 0 = n n ^ n = 0 对于这道题来说,所有数依次异或剩下的就是那个数了 class Solution(object): def singleNumber(self, nums): ans = 0 for i in nums…

136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. (Easy) Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 分析: 第一问属于技巧题,做过就会,…

Single Number I : Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Solution: 解法不少,贴一种: class…

Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…

原题地址https://leetcode.com/problems/single-number-ii/ 题目描述Given an array of integers, every element appears three times except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现三次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime co…

LeetCode 137. Single Number II(只出现一次的数字 II)…

LeetCode 136. Single Number(只出现一次的数字)…

Single Number III Given 2*n + 2 numbers, every numbers occurs twice except two, find them. Example Given [1,2,2,3,4,4,5,3] return 1 and 5 Challenge O(n) time, O(1) extra space. 可耻的百度了..点这里 还是好理解的.当然不一定要用最低位的1,任意找一个1即可.不过有lowbit = xor & -xor 这个公式当然是这个…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…

Given an array of integers, every element appears twice except for one. Find that single one. 思路: 最经典的方法,利用两个相同的数异或结果为0的性质,则将整个数组进行异或,相同的数俩俩异或,最后得到的就是那个single number,复杂度是O(n) 代码: class Solution { public: int singleNumber(vector<int>& nums) { int…