CodeForces 116B【二分匹配】

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CodeForces 116B【二分匹配】

思路: 暴力..我不会呀.. YY一个二分匹配嘛,然后数组开小了.GG for an hour. #include <bits/stdc++.h> using namespace std; typedef long long LL; int cy[110]; int cx[110]; int n,m; char ma[15][15]; int g[15][15]; int mma[110][110]; int dx[4]={1,-1,0,0}; int dy[4]={0,0,-1,1}; bo…

POJ 1274 The Perfect Stall、HDU 2063 过山车（最大流做二分匹配）

The Perfect Stall Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 24081 Accepted: 10695 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering p…

[kuangbin带你飞]专题十匹配问题二分匹配部分

刚回到家开了二分匹配专题手握xyl模板奋力写写写终于写完了一群模板题 A hdu1045 对这个图进行行列的重写给每个位置赋予新的行列使不能相互打到的位置拥有不同的行与列然后左行右列边是新的坐标求最大匹配 #include<stdio.h> #include<string.h> #include<algorithm> #include<math.h> #include<map> #include<string>…

BZOJ 1189 二分匹配 || 最大流

1189: [HNOI2007]紧急疏散evacuate Time Limit: 10 Sec Memory Limit: 162 MBSubmit: 1155 Solved: 420[Submit][Status][Discuss] Description 发生了火警,所有人员需要紧急疏散!假设每个房间是一个N M的矩形区域.每个格子如果是'.',那么表示这是一块空地:如果是'X',那么表示这是一面墙,如果是'D',那么表示这是一扇门,人们可以从这儿撤出房间.已知门一定在房间的边界上,并且…

Kingdom of Obsession---hdu5943（二分匹配）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5943 题意:给你两个数n, s 然后让你判断是否存在(s+1, s+2, s+3, ... , s+n )的任意排列方式使得每个数都满足当前数num,与num所在位置 pos 形成num%pos=0: 例如 n = 4 , s = 11 num = {13, 14, 15, 12} pos = {1, 2, 3, 4} 每个num与之对应的pos都是num%pos = 0;的关系…

poj 2060 Taxi Cab Scheme (二分匹配)

Taxi Cab Scheme Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 5710 Accepted: 2393 Description Running a taxi station is not all that simple. Apart from the obvious demand for a centralised coordination of the cabs in order to pick up…

[ACM_图论] Sorting Slides(挑选幻灯片，二分匹配，中等）

Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transparencies on one big heap. Before giving the talk, he has to sort the slides. Being a kind of minima…