LeetCode:汇总区间【228】】的更多相关文章

LeetCode:汇总区间[228] 题目描述 给定一个无重复元素的有序整数数组,返回数组区间范围的汇总. 示例 1: 输入: [0,1,2,4,5,7] 输出: ["0->2","4->5","7"] 解释: 0,1,2 可组成一个连续的区间; 4,5 可组成一个连续的区间. 示例 2: 输入: [0,2,3,4,6,8,9] 输出: ["0","2->4","6",…
228. 汇总区间 给定一个无重复元素的有序整数数组,返回数组区间范围的汇总. 示例 1: 输入: [0,1,2,4,5,7] 输出: ["0->2","4->5","7"] 解释: 0,1,2 可组成一个连续的区间; 4,5 可组成一个连续的区间. 示例 2: 输入: [0,2,3,4,6,8,9] 输出: ["0","2->4","6","8->9&…
#整体思路:使用堆栈,在Python中可以使用列表代替:如果a[i]-a[i-1]==1,就要将a[i]合并到之前的区间里,#所以我们队首位元素开辟一个区间为[a[0],a[0]]#做最后汇总时候,如果区间内前后元素相等,就直接str(),如果不相等就用->分割:class Solution: def summaryRanges(self, nums): """ :type nums: List[int] :rtype: List[str] ""&q…
题目链接: https://leetcode-cn.com/problems/summary-ranges 难度:中等 通过率:48.9% 题目描述: 给定一个无重复元素的有序整数数组,返回数组区间范围的汇总. 示例: 示例 1: 输入: [0,1,2,4,5,7] 输出: ["0->2","4->5","7"] 解释: 0,1,2 可组成一个连续的区间; 4,5 可组成一个连续的区间. 示例 2: 输入: [0,2,3,4,6,8,…
给定一个无重复元素的有序整数数组,返回数组中区间范围的汇总. 示例 1: 输入: [0,1,2,4,5,7]输出: ["0->2","4->5","7"]示例 2: 输入: [0,2,3,4,6,8,9]输出: ["0","2->4","6","8->9"] 详见:https://leetcode.com/problems/summary-ra…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
ji那天好像是周六.....吃完饭意识到貌似今天要有比赛(有题解当然要做啦),跑回寝室发现周日才开始233333 ====================================================================== leetcode217 Contains Duplicate leetcode219 Contains Duplicate II leetcode228 Summary Ranges ==============================…
给定一个无重复元素的有序整数数组,返回数组区间范围的汇总. 示例 1: 输入: [0,1,2,4,5,7] 输出: ["0->2","4->5","7"] 解释: 0,1,2 可组成一个连续的区间; 4,5 可组成一个连续的区间. 示例 2: 输入: [0,2,3,4,6,8,9] 输出: ["0","2->4","6","8->9"] 解释:…
给定一组区间,将所有区间重叠的部分合并起来. e.g. 给出 { [1, 3], [2, 6], [8, 10], [15, 18] },返回 { [1, 6], [8, 10], [15, 18] } 区间使用结构体(C++)或类(Java)表示 struct Interval { int start; int end; Interval() : start(), end() {} Interval(int s, int e) : start(s), end(e) {} }; 原理很简单,按区…
合并区间     给出一个区间的集合,请合并所有重叠的区间. 示例 1: 输入: [[1,3],[2,6],[8,10],[15,18]] 输出: [[1,6],[8,10],[15,18]] 解释: 区间 [1,3] 和 [2,6] 重叠, 将它们合并为 [1,6]. 示例 2: 输入: [[1,4],[4,5]] 输出: [[1,5]] 解释: 区间 [1,4] 和 [4,5] 可被视为重叠区间. 思路:我们采用非常直观的思维,观察各个区间,既然要对区间排列,首先对区间排序,使其按照左端点的…
区间和的个数 给定一个整数数组 nums,返回区间和在 [lower, upper] 之间的个数,包含 lower 和 upper.区间和 S(i, j) 表示在 nums 中,位置从 i 到 j 的元素之和,包含 i 和 j (i ≤ j). 说明:最直观的算法复杂度是 O(n2) ,请在此基础上优化你的算法. 示例: 输入: nums = [-2,5,-1], lower = -2, upper = 2, 输出: 3 解释: 3个区间分别是: [0,0], [2,2], [0,2],它们表示…
795. 区间子数组个数 给定一个元素都是正整数的数组A ,正整数 L 以及 R (L <= R). 求连续.非空且其中最大元素满足大于等于L 小于等于R的子数组个数. 例如 : 输入: A = [2, 1, 4, 3] L = 2 R = 3 输出: 3 解释: 满足条件的子数组: [2], [2, 1], [3]. 注意: L, R 和 A[i] 都是整数,范围在 [0, 10^9]. 数组 A 的长度范围在[1, 50000]. PS: 大佬简单易懂的代码, 下面有我写的那个,不过效率又低…
327. 区间和的个数 给定一个整数数组 nums,返回区间和在 [lower, upper] 之间的个数,包含 lower 和 upper. 区间和 S(i, j) 表示在 nums 中,位置从 i 到 j 的元素之和,包含 i 和 j (i ≤ j). 说明: 最直观的算法复杂度是 O(n2) ,请在此基础上优化你的算法. 示例: 输入: nums = [-2,5,-1], lower = -2, upper = 2, 输出: 3 解释: 3个区间分别是: [0,0], [2,2], [0,…
问题描述 给定两个由一些 闭区间 组成的列表,每个区间列表都是成对不相交的,并且已经排序. 返回这两个区间列表的交集. (形式上,闭区间 [a, b](其中 a <= b)表示实数 x 的集合,而 a <= x <= b.两个闭区间的交集是一组实数,要么为空集,要么为闭区间.例如,[1, 3] 和 [2, 4] 的交集为 [2, 3].) 示例: 输入:A = [[0,2],[5,10],[13,23],[24,25]], B = [[1,5],[8,12],[15,24],[25,26…
使用最简单的排序方法: /** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * Interval(int s, int e) { start = s; end = e; } * } */ public class Solution { public List<Interval> merge(List<…
class Solution { public: static bool cmp(vector<int> a,vector<int> b){ ]<b[]; } vector<vector<int>> merge(vector<vector<int>>& intervals) { vector<vector<int>> res; sort(intervals.begin(),intervals.en…
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…
数组篇 # 题名 刷题 通过率 难度 1 两数之和 C#LeetCode刷题之#1-两数之和(Two Sum) 43.1% 简单 4 两个排序数组的中位数 C#LeetCode刷题之#4-两个排序数组的中位数(Median of Two Sorted Arrays)-该题未达最优解 30.1% 困难 11 盛最多水的容器 C#LeetCode刷题之#11-盛最多水的容器(Container With Most Water) 37.9% 中等 15 三数之和 C#LeetCode刷题之#15-三数…
leetcode探索中级答案汇总: https://leetcode-cn.com/explore/interview/card/top-interview-questions-medium/ 1)数组和字符串: leetcode 15 三数之和(medium)排序+双指针 leetcode73 矩阵置零 (medium) 空间节省技巧 leetcode 49 字母异位词分组(medium)排序+哈希 leetcode 3 无重复字符的最长子串(medium) DP leetcode5 最长回文…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Example 2: Input: [0,2,3,4,6,8,9] Output: ["0","2->4"…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array nums, where the range of elements are in the inclusive range [lower, upper], return its missing ranges. Example: Input: nums = [0, 1, 3, 50, 75], lower = 0 and upper = 99,Output: ["2", "4->49", "51-…
终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…
Given a set of intervals, for each of the interval i, check if there exists an interval j whose start point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. For any interval i, you ne…
Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping. Note: You may assume the interval's end point is always bigger than its start point. Intervals like [1,2] and…
Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…
Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive.Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive. Note:A naive algorithm of O(n2) is trivial.…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…
Given a sorted integer array where the range of elements are [0, 99] inclusive, return its missing ranges.For example, given [0, 1, 3, 50, 75], return [“2”, “4->49”, “51->74”, “76->99”] 这道题让我们求缺失区间,跟之前那道Summary Ranges很类似,这道题让我们求缺失的空间,给了一个空间的范围[lo…