public ListNode reverseBetween(ListNode head, int m, int n) { if(head==null) return head; ListNode slow = head; ListNode fast = head; //find middle while(fast.next!=null) { fast = fast.next; if(fast.next!=null) { fast = fast.next; } else { slow = slo…

Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 递归的办法: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { v…

Reverse a singly linked list. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* reverseList(ListNode* head) { if (head == NUL…

Reverse a singly linked list  http://angelonotes.blogspot.tw/2011/08/reverse-singly-linked-list.html Source   1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 #include <stdio.h>   typedef st…

Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 之前做到Reverse Linked List II 倒置链表之二的时候我还纳闷怎么只有二没有一呢,原来真是忘了啊,现在才加上,这道题跟之前那道比起来简单不少,题目为了增加些许难度,让我们分别用…

#206.  Reverse Linked List Reverse a singly linked list. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* reverseList(ListNo…

Reverse a singly linked list. 这题因为palindrome linked list 的时候需要就顺便做了一下.利用三个指针:prev, now, next 相互倒腾就行. /** * Definition for singly-linked list. * function ListNode(val) { * this.val = val; * this.next = null; * } */ /** * @param {ListNode} head * @retu…

Reverse a singly linked list. 解题思路: 用Stack实现,JAVA实现如下: public ListNode reverseList(ListNode head) { if(head==null) return null; Stack<ListNode> stack =new Stack<ListNode>(); ListNode temp=head; while(temp!=null){ stack.push(temp); temp=temp.ne…

Reverse a singly linked list. 思路:没啥好说的.秒... ListNode* reverseList(ListNode* head) { ListNode * rList = NULL, * tmp = NULL; while(head != NULL) { tmp = rList; rList = head; head = head->next; rList->next = tmp; } return rList; }…

本来没想出来,刚才突然想到,可以用“头插法”来反转 Reverse Linked List My Submissions Question Total Accepted: 66556 Total Submissions: 182891 Difficulty: Easy Reverse a singly linked list. click to show more hints. Discuss中的递归解法: public ListNode reverseList(ListNode head) {…

Reverse a singly linked list. 参考http://www.2cto.com/kf/201110/106607.html 方法1: 讲每个节点的指针指向前面就可以. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution…

Reverse a singly linked list. 解法一:记录单链表每个节点的val,然后重新为单链表赋值.(取巧,仅仅是将val部分改变,原始node节点并没有改变) 代码如下: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution…

Reverse a singly linked list. 代码如下: the iterative solution:(c++) /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* reverseLis…

9 - Palindrome Number Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra…

题目描述: Reverse a singly linked list. 解题思路: 使用递归或者迭代的方法. 代码如下: 方法一:递归 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode reverseLi…

Reverse a singly linked list. package cn.magicdu; import cn.magicdu.extra.ListNode; public class _206_Reverse_Linked_List { /** * 迭代 * @param head * @return */ public ListNode reverseList(ListNode head) { if (head == null || head.next == null) return…

Reverse a singly linked list. 使用栈 public class Solution { public ListNode ReverseList(ListNode head) { if (head == null) { return null; } Stack<int> stack = new Stack<int>(); stack.Push(head.val); var node = head.next; while (node != null) { s…

Question Reverse a singly linked list. Solution 1 -- Iterative Remember to set head.next = null or it will report "memory limit exceeds" error. /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * List…

题目: Reverse a singly linked list. 提示: 此题不难,可以用迭代或者递归两种方法求解.记得要把原来的链表头的next置为NULL: 代码: 迭代: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { pub…

题目内容 题目来源:LeetCode Reverse a singly linked list. 题目思路 这个属于经典问题,链表反转的思路基本上已经非常固定了.有两种非常常见的方法:1.三指针法 2.头插法 这个题目用到的是三指针法. 方法:设立三个指针,分别叫做pre, curr, next.这三个指针的功能分别是:现用next保存curr的下一个结点,免得以后找不到了.然后将curr指向pre,这一步实现了反转,然后让pre指向curr, curr指向next. 具体的解释这个博客写的非常…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Reverse a singly linked list. (二)解题 题目大意:反转一个单向链表 解题思路:题目要求用迭代和递归分别实现 迭代版本: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNod…

1. Reverse Linked List 题目链接 题目要求: Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 初想用递归来实现应该会挺好的,但最终运行时间有点久,达到72ms,虽然没超时.具体程序如下: /** * Definition for singly-linked list. *…

题目描述: Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? Subscribe to see which companies asked this question 分析: 注意这个数据结构,这是一个链表,要求颠倒顺序.考虑设置两个变量,来表…

Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? 反转一个单链表. 示例: 输入: 1->2->…

Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? 解法一:(C++)利用迭代的方法依次将链表元素放在新链表的…

面试题16:反转链表 提交网址: http://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca?tpId=13&tqId=11168 或 https://leetcode.com/problems/reverse-linked-list/ Total Accepted: 101523  Total Submissions: 258623  Difficulty: Easy Reverse a singly linked lis…

Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? -----------------------------…

题目要求 Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL 题目分析及思路 给定一个单链表,要求得到它的逆序.可以使用列表对链表结点进行保存,之后新建一个列表对链表的逆序进行保存.最后返回新建列表的第一个元素即可. python代码 # Definition for singly-linked list. #…

Reverse a singly linked list. Example:           Input: 1->2->3->4->5->NULL                   Output: 5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? 解…

Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL # Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Sol…