Problem Description As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes…

Problem Description As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes…

Train Problem I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 51413    Accepted Submission(s): 19341 Problem Description As the new term comes, the Ignatius Train Station is very busy nowaday…

杭电1002http://acm.hdu.edu.cn/showproblem.php?pid=1022 Train Problem I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 25276    Accepted Submission(s): 9529 Problem Description As the new term com…

Train Problem I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 25773    Accepted Submission(s): 9729 Problem Description As the new term comes, the Ignatius Train Station is very busy nowadays.…

题目大意: 给你一个n 代表有n列 火车,  第一个给你的一个字符串 代表即将进入到轨道上火车的编号顺序, 第二个字符串代表的是 火车出来之后到顺序, 分析一下就知道这,这个问题就是栈, 先进后出吗, 就是问你这个编号有没有可能出现, 有可能的话输出顺序,没可能直接输出No 题目分析: 我们用栈进行模拟, 先判断是否有这种出栈的可能, 假如有这种可能的话我们在模拟 一遍出栈的顺就行了. 每一次有新元素入栈我们就判断他是否雨 第二个字符串的第一个元素是否相等, 假如一样, 就让次元素出栈. 代码…

Description As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes a proble…

这道题是道简单的栈模拟题,只要按照真实情况用栈进行模拟即可: #include<stdio.h> #include<string.h> #include<stack> using namespace std; int main() { ]; ], s2[]; stack <char> s; while(~scanf("%d %s%s",&n,s1,s2)) { while(!s.empty()) s.pop(); //也可以不写这…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1042 栈的模拟,题目大意是已知元素次序, 判断出栈次序是否合理. 需要考虑到各种情况, 分类处理. 常见错误:使用前未清空栈 使用STL思路较为清晰 代码附上, 欢迎各位大神指点~~ #include <cstdio> #include <stack> #include <iostream> #include <vector> using namespace s…

#include<stdio.h> #include<string.h> #include<queue> #include<stack> #define N 10 using namespace std; void Q(int n) { int m; char s[N]; queue<int>Q; while(n--) { scanf("%s", s); ) { scanf("%d", &m); Q…