hdu 2647 Reward Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble…

Best Reward Problem's Link:   http://acm.hdu.edu.cn/showproblem.php?pid=3613 Mean: 给你一个字符串,每个字符都有一个权值(可能为负),你需要将这个字符串分成两个子串,使得这两个子串的价值之和最大.一个子串价值的计算方法:如果这个子串是回文串,那么价值就是这个子串所有字符权值之和:否则价值为0. analyse: 扩展KMP算法运用.总体思路:找出所有包含第一个字母的回文串和包含最后一个字母的回文串,然后O(n)扫一…

HDU   3613 Description After an uphill battle, General Li won a great victory. Now the head of state decide to reward him with honor and treasures for his great exploit. One of these treasures is a necklace made up of 26 different kinds of gemstones,…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2647 Reward Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the reward…

Reward Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3015    Accepted Submission(s): 907 Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wan…

Reward Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5617    Accepted Submission(s): 1707 Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wa…

Reward                                    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)                                    Total Submission(s): 2647    Accepted Submission(s): 768 Problem Description       Dandel…

Reward Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 7   Accepted Submission(s) : 3 Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to…

题目来源:HDU 3613 Best Reward 题意:每一个字母相应一个权值 将给你的字符串分成两部分 假设一部分是回文 这部分的值就是每一个字母的权值之和 求一种分法使得2部分的和最大 思路:考虑扩展KMP 输出a串 得到a的反串b 求出f[0]和f[1] 和 extend[0]和extend[1] 正反求2次 枚举位置i 分成2部分0到i-1 和i到n-1 由于分成的2部分必须组成原字符串 就是不能多也不能少 那么推断i+extend[i]是否等于n 等于说明i到n-1这个部分是回文串…

Reward Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewards. The workers will compare their rewards ,a…