[Leetcode Week14]Maximum Binary Tree】的更多相关文章

Maximum Binary Tree 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/maximum-binary-tree/description/ Description Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in…
Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…
Construct Binary Tree from Inorder and Postorder Traversal 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/description/ Description Given inorder and postorder traversal of a tree, construct…
题目: Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum nu…
Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…
1.题目描述 2.分析 找出最大元素,然后分割数组调用. 3.代码 TreeNode* constructMaximumBinaryTree(vector<int>& nums) { int size = nums.size(); ) return NULL; TreeNode *dummy = ); maxcont(dummy->left, , size-, nums); return dummy->left; } void maxcont(TreeNode* &…
每次找到数组中的最大值,然后递归的构建左右树 public TreeNode constructMaximumBinaryTree(int[] nums) { if (nums.length==0) return null; return builder(nums,0,nums.length-1); } public TreeNode builder(int[] nums,int sta,int end) { /* 思路就是每次找到最大值,然后分为两个子数组递归构建左右树 */ if (sta>…
Leetcode之分治法专题-654. 最大二叉树(Maximum Binary Tree) 给定一个不含重复元素的整数数组.一个以此数组构建的最大二叉树定义如下: 二叉树的根是数组中的最大元素. 左子树是通过数组中最大值左边部分构造出的最大二叉树. 右子树是通过数组中最大值右边部分构造出的最大二叉树. 通过给定的数组构建最大二叉树,并且输出这个树的根节点. 示例 : 输入:[3,2,1,6,0,5] 输出:返回下面这棵树的根节点: 6 / \ 3 5 \ / 2 0 \ 1 提示: 给定的数组…
题目如下: We are given the root node of a maximum tree: a tree where every node has a value greater than any other value in its subtree. Just as in the previous problem, the given tree was constructed from an list A (root = Construct(A)) recursively with…
https://leetcode.com/problems/maximum-binary-tree-ii/ 在654. Maximum Binary Tree版本的建树基础上,在最后插入一个数. 新节点要么为根节点,原树为其左子树:要么将新节点插在右子树中. class Solution { public: TreeNode* insertIntoMaxTree(TreeNode* root, int val) { if(root == NULL) { root = new TreeNode(v…