UVa 10945 - Mother bear】的更多相关文章

题目大意:给一个字符串,判断是否回文(忽略大小写,忽略非字母字符). #include <cstdio> #include <cctype> #include <cstring> #define MAXN 100000 char str1[MAXN], str2[MAXN]; int main() { #ifdef LOCAL freopen("in", "r", stdin); #endif while (gets(str1))…
题目: http://uva.onlinejudge.org/external/128/12849.pdf #include <bits/stdc++.h> using namespace std; typedef long long LL ; typedef unsigned long long ULL ; typedef pair<int,int> pii; #define X first #define Y second ; ; ; double A[N][N] ; void…
http://www.fxguide.com/featured/pixars-opensubdiv-v2-a-detailed-look/ Pixar’s OpenSubdiv V2: A detailed look By Mike Seymour September 18, 2013 Subdivision is key modeling tool that allows greater accuracy and the OpenSubdiv project aims to standardi…
http://www.cgw.com/Publications/CGW/2012/Volume-35-Issue-4-June-July-2012/The-Royal-Treatment.aspx The Royal Treatment By: Barbara Robertson Pixars extraordinary run of successful films starring male characters took a courageous turn in June with the…
A. Masha and Bears time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car…
Description A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into…
Problem description A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can cli…
uva 10192 Vacation The Problem You are planning to take some rest and to go out on vacation, but you really don't know which cities you should visit. So, you ask your parents for help. Your mother says "My son, you MUST visit Paris, Madrid, Lisboa an…
错排问题是一种特殊的排列问题. 模型:把n个元素依次标上1,2,3.......n,求每一个元素都不在自己位置的排列数. 运用容斥原理,我们有两种解决方法: 1. 总的排列方法有A(n,n),即n!,设Ai 表示数i在第i个位置的全体排列,显然有Ai =(n-1)!. 同理可得Ai∩Aj=(n-2)!,那么每一个元素都不在原来位置的排列就有n!-C(n,1)*(n-1)!+C(n,2)*(n-2)!-.....+(-1)^n *C(n,n)*1!. 也就是n!*(a-1/1!+1/2!-1/3!…
F. Bear and Fair Set time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a grizzly bear. He is big and dreadful. You were chilling in the forest when you suddenly met him. It's very u…