1.题目 35. Search Insert Position Easy 1781214Add to ListShare Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in th…

Description Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Example 1: Input: [,,,], Output: Example…

这道题难度较低,没有必要作说明. Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 35: Search Insert Positionhttps://oj.leetcode.com/problems/search-insert-position/ Given a sorted array and a target value, return the index if the target is found.If not, return the index…

leetcode - 35. Search Insert Position - Easy descrition Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the arr…

704. Binary Search 1.使用start+1 < end,这样保证最后剩两个数 2.mid = start + (end - start)/2,这样避免接近max-int导致的溢出 3.start.end直接等于mid 4.最后比较两个位置 class Solution { public: int search(vector<int>& nums, int target) { if(nums.empty()) ; ; ; int mid; < end){ m…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Example 1: Input: [1,3,5,6], 5 Output: 2 Example 2:…

Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,…

Sqrt(x) Implement int sqrt(int x). Compute and return the square root of x. 注:这里的输入输出都是整数说明不会出现 sqrt(7)这种情况,思路一就是应用二分法进行查找.每次给出中间值,然后比对cur的平方与目标值的大小.需要先设定两个变量用来存放左右游标. 这里要考虑一下整型溢出的问题,另外,即使不能开出整数的也要近似给出整数部分,不能忽略. 代码如下: int Solution::mySqrt(int x) { //…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Example 1: Input: [1,3,5,6], 5 Output: 2 Example 2:…