Problem Statement You are given a string S consisting of digits between 1 and 9, inclusive. You can insert the letter + into some of the positions (possibly none) between two letters in this string. Here, + must not occur consecutively after insertio…

Time limit : 2sec / Memory limit : 256MB Score : 300 points Problem Statement You are given a string S consisting of digits between 1 and 9, inclusive. You can insert the letter + into some of the positions (possibly none) between two letters in this…

xor是满足交换律的,展开后发现仅仅要能高速求出 [1mod1....1modn],....,[nmod1...nmodn]的矩阵的xor即可了....然后找个规律 C. Magic Formulas time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output People in the Tomskaya region like magi…

这个题就是求出给的公式的结果. 仅仅要知道异或运算满足交换律跟结合律即可了.之后就是化简公式. #include<map> #include<string> #include<cstring> #include<cstdio> #include<cstdlib> #include<cmath> #include<queue> #include<vector> #include<iostream> #…

You are given a string S consisting of digits between 1 and 9, inclusive. You can insert the letter + into some of the positions (possibly none) between two letters in this string. Here, + must not occur consecutively after insertion. All strings tha…

C. Magic Formulas time limit per test:2 seconds     memory limit per test:256 megabytes   input standard input output standard output People in the Tomskaya region like magic formulas very much. You can see some of them below. Imagine you are given a…

cf的一次数学场... 递推 C 题意:长度<=n的数只含有7或8的个数 分析:每一位都有2种可能,累加不同长度的方案数就是总方案数 组合 G 题意:将5个苹果和3个梨放进n个不同的盒子里的方案数. 分析:经典的组合题目:C(n+5-1, 5) * C(n+3-1, 3).因为可以同一个盒子放多个苹果或梨,在n基础上多k-1个,看成每个盒子放一个. 组合 H 题意:将5个车放在n*n的棋盘上的方案数. 分析:也是经典的题目,先选行,再全排列,即C (n, 5) * A (n, 5). 枚举 I…

解题思路是: Q=q1^q2.......^qn = p1^p2......^pn^((1%1)^....(1%n))^((2%1)^......(2%n))^.... 故Q的求解过程分成两部分 第一部分是求p1^p2......^pn 第二部分是求((1%1)^....(1%n))^((2%1)^......(2%n))^.... 将其化成矩形的形式 1%1   1%2  ...........  1%n 2%1   2%2  ............ 2%n ................…

题目 比赛的时候找出规律了,但是找的有点慢了,写代码的时候出了问题,也没交对,还掉分了.... 还是先总结一下位移或的性质吧: 1.  交换律 a ^ b = b ^ a 2. 结合律 (a^b) ^ c = a ^ (b^c) 3. 0^a = a; 4. a^a = 0;    a^a^a = a; 5.   知道a,b,c中任意两个就能推知第三个.      a^b = c 两边同时与a异或得: a ^ (a^b) = a^c 即 0^b = a^c  亦即 b = a^c 四个也是一样…

代码: public static void dropDownList(string[] datas, string filePath) { HSSFWorkbook workbook = new HSSFWorkbook(); ISheet sheet = workbook.CreateSheet("下拉列表测试"); ISheet hidden = workbook.CreateSheet("hidden"); //数据源sheet页不显示 workbook.S…