Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Hide Tags Bit Manipulation   数组中的数均出现3…
题目描述: 给定一个包含n个整数的数组,除了一个数出现一次外所有的整数均出现三次,找出这个只出现一次的整数. 题目来源: http://oj.leetcode.com/problems/single-number-ii/ 题目分析: 对于除出现一次之外的所有的整数,其二进制表示中每一位1出现的次数是3的整数倍,将所有这些1清零,剩下的就是最终的数. 用ones记录到当前计算的变量为止,二进制1出现“1次”(mod 3 之后的 1)的数位.用twos记录到当前计算的变量为止,二进制1出现“2次”(…
136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…
[LeetCode]137. Single Number II 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/single-number-ii/description/ 题目描述: Given an array of integers, every element appears three times except for one, which appears exactly once. Find that singl…
LeetCode 137. Single Number II(只出现一次的数字 II)…
剑指 Offer 40. 最小的k个数 Offer_40 题目描述 解法一:排序后取前k个数 /** * 题目描述:输入整数数组 arr ,找出其中最小的 k 个数.例如,输入4.5.1.6.2.7.3.8这8个数字,则最小的4个数字是1.2.3.4. */ /** * 方法一:先对数字进行排序,然后依次找到最小的k个数 */ public class Offer_40 { public int[] getLeastNumbers(int[] arr, int k) { if(arr == nu…
剑指 Offer 40. 最小的k个数 输入整数数组 arr ,找出其中最小的 k 个数.例如,输入4.5.1.6.2.7.3.8这8个数字,则最小的4个数字是1.2.3.4. 示例 1: 输入:arr = [3,2,1], k = 2 输出:[1,2] 或者 [2,1] 示例 2: 输入:arr = [0,1,2,1], k = 1 输出:[0] 限制: 0 <= k <= arr.length <= 10000 0 <= arr[i] <= 10000 做题思路:其实做这…
原题地址https://leetcode.com/problems/single-number-ii/ 题目描述Given an array of integers, every element appears three times except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现三次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime co…
Single Number II Given an array of integers, every element appears threetimes except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解法一:开辟map记录次数 class So…
本文参考自<剑指offer>一书,代码采用Java语言. 更多:<剑指Offer>Java实现合集   题目 输入n个整数,找出其中最小的k个数.例如输入4.5.1.6.2.7.3.8这8个数字,则最小的4个数字是1.2.3.4. 思路 思路一:同剑指offer(39) 数组中出现次数超过一半的数字中使用partition()方法,基于数组的第k个数字调整,使得更小的k个数字都在数组左边即可. 思路二:依次遍历n个整数,用一个容器存放最小的k个数字,每遇到比容器中最大的数字还小的数…
Given an array of integers, every element appears three times except for one, which appears exactly once. Find that single one. 题意: 在一个整型数组里,只有一个数字出现一次,其他数字都出现了3次,求这个只出现一次的数字(single number). 这真是非常非常有意思的一道题目.如果直接统计各数字出现的次数当然也能达到目的,不过空间复杂度为O(N).能否用O(1)…
Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…
题目意思:一个int数组,有一个数只出现一次,其他数均出现三次,找到这个唯一数 思路: 1.将所有数用2进制表示,计算每一位的数字和  1*3*n1+0*3*n2+c   唯一数对应位的数字(0或者1) 要求具有牢固的位运算基础 eg  10001010  10001010 10001010   10101001   10101001 10101001 11001010                   7,1,3,0,7,0,4,3 则唯一数为1,1,0,0,1,0,1,0 class So…
翻译 给定一个整型数组,除了某个元素外其余的均出现了三次. 找出这个元素. 备注: 你的算法应该是线性时间复杂度. 你能够不用额外的空间来实现它吗? 原文 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you…
Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…
题目描述 一个整型数组里除了两个数字之外,其他的数字都出现了偶数次.请写程序找出这两个只出现一次的数字. 题目地址 https://www.nowcoder.com/practice/e02fdb54d7524710a7d664d082bb7811?tpId=13&tqId=11193&rp=2&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking 思路 思路1:考虑用哈希表的方法,但是空间复…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complex…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路:用变量分别存储出现一次.两次.三次的number 出现一次的numbe…
题目: Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题解: The code seems tricky and hard…
传送门 Description Given an array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra me…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? public class Solution { public int sin…
Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? class Solution(object): def singleNum…
Given an array of integers, every element appears three times except for one. Find that single one. 代码如下: public class Solution { public int singleNumber(int[] nums) { if(nums.length==1||nums.length==2) return nums[0]; Arrays.sort(nums); for(int i=0;…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 求出数组中只出现一次的数,剩下的都是三次. /** * Created by…
原题地址 遍历所有数字,统计每一位出现的次数,模3即为只出现一次的数字在那一位的情况. 代码: int singleNumber(int A[], int n) { ] = {}; ; i < n; i++) { ; j < ; j++) { count[j] += A[i] & ; A[i] >>= ; } } ; ; j < ; j++) { res += (count[j] % ) << j; } return res; }…
题目描述: Given an array of integers, every element appears three times except for one. Find that single one. 解题思路: 具体参考Detailed explanation and generalization of the bitwise operation method for single numbers 讲的实在是很全面,而且拓展到了一般的情况,膜!! 代码如下: public class…
Given an array of integers, every element appears three times except for one, which appears exactly once. Find that single one.Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? class Solut…
Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解题思路一: 一个int的长度是32,因此可以开一个长度为32的数组,表示…
给定一个整型数组,除了一个元素只出现一次外,其余每个元素都出现了三次.求出那个只出现一次的数.注意:你的算法应该具有线性的时间复杂度.你能否不使用额外的内存来实现?详见:https://leetcode.com/problems/single-number-ii/description/ Java实现: 建立一个32位的数组,来统计每一位上1出现的个数,如果某一位上为1的话,那么如果该整数出现了三次,对3去余为0,把每个数的对应位都加起来对3取余,最终剩下来的那个数就是单独的数字. 参考:htt…
题目描述 一个整型数组里除了两个数字之外,其他的数字都出现了两次.请写程序找出这两个只出现一次的数字. [思路]此题考察的是异或运算的特点:即两个相同的数异或结果为0. 此题用了两次异或运算特点: (1)第一次使用异或运算,得到了两个只出现一次的数相异或的结果. (2)因为两个只出现一次的数肯定不同,即他们的异或结果一定不为0,一定有一个位上有1.另外一个此位上没有1,我们可以根据此位上是否有1,将整个数组重新划分成两部分,一部分此位上一定有1,另一部分此位上一定没有1,然后分别对每部分求异或,…