Sqrt(x) Implement int sqrt(int x). Compute and return the square root of x. 解法一:牛顿迭代法 求n的平方根,即求f(x)=x2-n的零点 设初始值为x0,注,不要设为0,以免出现除数为0,见后. 则过(x0,f(x0))点的切线为g(x)=f(x0)+f'(x0)*(x-x0) g(x)与x轴的交点为x1=x0-f(x0)/f'(x0) 递推关系为xn+1=xn-f(xn)/f'(xn) 当收敛时即为解. class…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:库函数 方法二:牛顿法 方法三:二分查找 日期 题目地址:https://leetcode.com/problems/sqrtx/description/ 题目描述 Implement int sqrt(int x). Compute and return the square root of x. x is guaranteed to be…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Implement int sqrt(int x). Compute and return the square root of x. (二)解题 实现sqrt(x),找到一个数,它的平方等于小于x的最接近x的数. class Solution { public: int mySqrt(int x) { int…

Sort Colors Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue. Here, we will use the integers 0, 1, and 2 to represent the color red, w…

Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a so…

Wildcard Matching Implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partia…

Surrounded Regions Given a 2D board containing 'X' and 'O', capture all regions surrounded by 'X'. A region is captured by flipping all 'O's into 'X's in that surrounded region. For example, X X X X X O O X X X O X X O X X After running your function…

package y2019.Algorithm.dynamicprogramming.easy; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.dynamicprogramming.easy * @ClassName: Rob * @Author: xiaof * @Description: 198. House Robber * You are a professional robber planning to rob…

Counting Bits Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example:For num = 5 you should return [0,1,1,2,1,2]. Follow up…

Add Digits Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. Follow up:Could you do it…