【[Leetcode 108]有序数组转二叉搜索树Convert Sorted Array to Binary Search Tree】的更多相关文章

[Leetcode 108]有序数组转二叉搜索树Convert Sorted Array to Binary Search Tree

[题目] 给出的升序排序的数组,个数必为奇数,要求形成二叉搜索(平衡)树. [思路] 辅助函数fun,[0,len]=>[0,mid-1]+[mid+1,len]. 当left>right,返回null. public TreeNode fun(int[] nums,int left,int right) { int mid=(right+left)/2; TreeNode tmp=new TreeNode(nums[mid]); if(right<left) return null;…

LeetCode 108. 将有序数组转换为二叉搜索树(Convert Sorted Array to Binary Search Tree) 14

108. 将有序数组转换为二叉搜索树 108. Convert Sorted Array to Binary Search Tree 题目描述 将一个按照升序排列的有序数组,转换为一棵高度平衡二叉搜索树. 本题中,一个高度平衡二叉树是指一个二叉树每个节点的左右两个子树的高度差的绝对值不超过 1. 每日一算法2019/5/17Day 14LeetCode108. Convert Sorted Array to Binary Search Tree 示例: 给定有序数组: [-10,-3,0,5,9…

[Swift]LeetCode108. 将有序数组转换为二叉搜索树 | Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…

[Swift]LeetCode109. 有序链表转换二叉搜索树 | Convert Sorted List to Binary Search Tree

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…

[LeetCode 109] - 将已排序链表转换为二叉搜索树 (Convert Sorted List to Binary Search Tree)

问题 给出一个元素以递增序列排序的单链表,将其转换为一棵高度平衡的二叉搜索树. 初始思路 二叉搜索树高度平衡,意味着左右子树的高度要平衡.根据二叉树左子树节点小于根节点,右子树节点大于根节点的性质:我们在待选节点中选择值为中位数的节点作为根节点,所有小于中位数的节点作为左子树,所有大于中位数的节点作为右子树,即可满足高度平衡的要求.由于题目给出的已经是排好序的单链表,我们只要每次选择中间的节点即可.然后通过递归处理左右子树,最终完成高度平衡二叉搜索树的构建. 最终完成代码如下: class So…

LeetCode 108. Convert Sorted Array to Binary Search Tree （将有序数组转换成BST）

108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the tw…

[LeetCode] 108. Convert Sorted Array to Binary Search Tree ☆(升序数组转换成一个平衡二叉树)

108. Convert Sorted Array to Binary Search Tree 描述 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the…

108. Convert Sorted Array to Binary Search Tree 109. Convert Sorted List to Binary Search Tree -- 将有序数组或有序链表转成平衡二叉排序树

108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *ri…

37. leetcode 108. Convert Sorted Array to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 思路:利用一个有序数组构建一个平衡二叉排序树.直接递归构建,取中间的元素为根节点,然后分别构建左子树和右子树.…

leetcode 108. Convert Sorted Array to Binary Search Tree 、109. Convert Sorted List to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 这个题使用二分查找,主要要注意边界条件. 如果left > right,就返回NULL.每次更新的时候是mid-1,mid+1. 自己推一下基本就可以验证了. class Solution { public: TreeNode* sortedArrayToBST(vector<int>& nums) { ,nums.size() - ); } TreeNode* ToBST(vecto…