Greedy Gift Givers A group of NP (2 ≤ NP ≤ 10) uniquely named friends has decided to exchange gifts of money. Each of these friends might or might not give some money to any or all of the other friends. Likewise, each friend might or might not receiv…

B. The Best Gift time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Emily's birthday is next week and Jack has decided to buy a present for her. He knows she loves books so he goes to the loc…

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Gift Hunting Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1418 Accepted Submission(s): 471 Problem Description After winning two coupons for the largest shopping mart in your city, you can't wa…

B. The Best Gift 题目连接: http://www.codeforces.com/contest/609/problem/B Description Emily's birthday is next week and Jack has decided to buy a present for her. He knows she loves books so he goes to the local bookshop, where there are n books on sale…

GTY's birthday gift                                                                       Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)                                                                            …

1328 - A Gift from the Setter   Problem setting is somewhat of a cruel task of throwing something at the contestants and having them scratch their head to derive a solution. In this problem, the setter is a bit kind and has decided to gift the contes…

 Greedy Gift Givers  The Problem This problem involves determining, for a group of gift-giving friends, how much more each person gives than they receive (and vice versa for those that view gift-giving with cynicism). In this problem each person sets…

GTY's birthday gift Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)  [Problem Description] FFZ's birthday is coming. GTY wants to give a gift to ZZF. He asked his gay friends what he should give to ZZF. One of them…

Greedy Gift Givers 贪婪的送礼者 对于一群(NP个)要互送礼物的朋友,GY要确定每个人送出的钱比收到的多多少. 在这一个问题中,每个人都准备了一些钱来送礼物,而这些钱将会被平均分给那些将收到他的礼物的人. 然而,在任何一群朋友中,有些人将送出较多的礼物(可能是因为有较多的朋友),有些人有准备了较多的钱. 给出一群朋友,没有人的名字会长于 14 字符,给出每个人将花在送礼上的钱,和将收到他的礼物的人的列表, 请确定每个人收到的比送出的钱多的数目. PROGRAM NAME: gi…

Greedy Gift Givers A group of NP (2 ≤ NP ≤ 10) uniquely named friends hasdecided to exchange gifts of money. Each of these friends might ormight not give some money to any or all of the other friends.Likewise, each friend might or might not receive m…

Ch’s gift Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1354    Accepted Submission(s): 496 Problem Description Mr. Cui is working off-campus and he misses his girl friend very much. After a w…

题目大意: N个物品,物品间有M组关系,每个物品有一个ai的代价,满足关系后会得到bi的值 求 max(sigma(bi)/sigma(ai)) 题解: 很明显的最大权闭合子图,只不过需要处理分数. 这里二分一个答案g 然后直接求sigma(b[i])-sigma(a[i]*g)即可 其中把图中的ai都改成ai*g即可 注意整数处理 #include <algorithm> #include <iostream> #include <cstdlib> #include…

CF76A.Gift 题意:noi2014魔法森林弱化版QwQ,最小化\(max(g_i)*G + max(s_i)*S\)的最小生成树 考虑按g升序加边,用已在生成树中的边和新加入的边求当前最小生成树. 复杂度\(O(nm)\) vector真好用 #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <vector> usi…

Greedy Gift Givers A group of NP (2 ≤ NP ≤ 10) uniquely named friends has decided to exchange gifts of money. Each of these friends might or might not give some money to any or all of the other friends. Likewise, each friend might or might not receiv…

Mr. Cui is working off-campus and he misses his girl friend very much. After a whole night tossing and turning, he decides to get to his girl friend's city and of course, with well-chosen gifts. He knows neither too low the price could a gift be sinc…

[CF506E]Mr. Kitayuta's Gift 题意:给你一个字符串s,你需要在s中插入n个字符(小写字母),每个字符可以被插在任意位置.问可以得到多少种本质不同的字符串,使得这个串是回文的.答案对10007取模. $|s|\le 200,n\le 10^9$ 题解:神题. 首先由于题目要求本质不同,所以我们为了防止重复,考虑从两边向中间不断复原回文串,如果新加入的字符与s两端(或一端)的字符相同,则匹配成功,继续匹配下一个字符.也就是说我们取的是s在回文串中最外面的出现位置. 为了方便…

GTY's math problem Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 0    Accepted Submission(s): 0 Problem Description GTY is a GodBull who will get an Au in NOI . To have more time to learn alg…

 Problem D. Gift?!  The Problem There is a beautiful river in a small village. N rocks are arranged in a straight line numbered 1 to N from left bank to the right bank, as shown below. [Left Bank] - [Rock1] - [Rock2] - [Rock3] - [Rock4] ... [Rock n]…

The kingdom of Olympia consists of N cities and M bidirectional roads. Each road connects exactly two cities and two cities can be connected with more than one road. Also it possible that some roads connect city with itself making a loop. All roads a…

Description Farmer John's nemesis, Farmer Nhoj, has NN cows (1≤N≤10^5), conveniently numbered 1…N. They have  unexpectedly turned up at Farmer John's farm, so the unfailingly polite Farmer John is attempting to  give them gifts.To this end, Farmer Jo…

912E - Prime Gift 思路: 折半枚举+二分check 将素数分成两个集合(最好按奇偶位置来,保证两集合个数相近),这样每个集合枚举出来的小于1e18的积个数小于1e6. 然后二分答案,check时枚举其中一个集合,然后找到另外一个集合小于mid/该元素的元素有多少个,这里用到一个双指针的技巧将复杂度降到O(n):一个集合从大到小枚举,那么mid/该元素就会逐渐变大,那么直接从上次找到的位置往后找就可以了,因为答案肯定在后面. 代码: #include<bits/stdc++.h>…

题目链接:Prime Gift 题意: 给出了n(1<=n<=16)个互不相同的质数pi(2<=pi<=100),现在要求第k大个约数全在所给质数集的数.(保证这个数不超过1e18) 题解: 如果暴力dfs的话肯定超时间,其实给的n数据范围最大是16是一个很奇妙的数(一般折半枚举基本上是这样的数据范围@.@-).所以想到折半枚举,把所有的质数分成两份求出每份中所有小于1e18的满足条件的数.然后二分答案,写cheak函数时遍历第一个集合,对第二个集合二分(折半枚举基本上这个套路).…

A. Mr. Kitayuta's Gift time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Mr. Kitayuta has kindly given you a string s consisting of lowercase English letters. You are asked to insert exactly…

2056: gift? 高精度? Time Limit: 10 Sec  Memory Limit: 1 MB Description   Input 输入的第一行为一个整数t. 接下来t行,每行包含九个自然数. Output 输出t行 每行一个整数,表示2^a+2^b+2^c+2^d+2^e+2^f+2^g+2^h+i. Sample Input 1 21 30 0 0 0 0 0 0 2147483647 Sample Output 3223322629 HINT  [数据规模]40% t<…

地址:http://acm.split.hdu.edu.cn/showproblem.php?pid=6162 题目: Ch’s gift Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 526    Accepted Submission(s): 177 Problem Description Mr. Cui is working of…

Ch’s gift Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 662    Accepted Submission(s): 229 Problem Description Mr. Cui is working off-campus and he misses his girl friend very much. After a wh…

Ch’s gift Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2534    Accepted Submission(s): 887 题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=6162 Problem Description Mr. Cui is working off-campu…

题意:就5种盒子,给出每个盒子个数,盒子总数,每个人选择这个盒子的概率.求这个人选择哪个盒子取得第一个朋友的概率最大,最大多少 dp[N][sta]表示当前第N个人面临状态sta(选择盒子的状态可以用13进制数表示)时的概率, 那么转移就是dp[N][sta]=sum(dp[N-1][sta-1]*G[n][k]) (表示第N个人选择第k个盒子) 那么答案应该是max(P(第1个人选择i号盒子)/总状态概率)(i<=5) #include <map> #include <set&g…

题目描述 Farmer John's nemesis, Farmer Nhoj, has NN cows (1 \leq N \leq 10^51≤N≤105 ), conveniently numbered 1 \dots N1…N . They have unexpectedly turned up at Farmer John's farm, so the unfailingly polite Farmer John is attempting to give them gifts. To…