POJ3267——The Cow Lexicon(动态规划)】的更多相关文章

The Cow Lexicon DescriptionFew know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words, each containing no more 25 of the characters 'a'..'z'. Their cowmunication system, based on mooing, is not very accurate; sometimes they hear word…
The Cow Lexicon Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9041   Accepted: 4293 Description Few know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words, each containing no more 25 of the characters 'a'..'z'. Their c…
The Cow Lexicon Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 8167   Accepted: 3845 Description Few know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words, each containing no more 25 of the characters 'a'..'z'. Their c…
题目大意:给定一个字符串和一本字典,问至少需要删除多少个字符才能匹配到字典中的单词序列.PS:是单词序列,而不是一个单词 思路:                                                                   动态规划 主要是知道状态方程的含义: 令dp[i]表示从message中第i个字符开始,到第L个字符(结尾处)这段区间所删除的字符数,初始化为dp[L]=0 (dp[i]的下标从0开始) 从message尾部向头部检索匹配,所以是下面的状…
题目链接. 分析: dp[i]表示母串从第i位起始的后缀所对应的最少去掉字母数. dp[i] = min(dp[i+res]+res-strlen(pa[j])); 其中res 为从第 i 位开始匹配 pa[j] 所需要的长度. 以下代码当做指针的练习,研究了几天C,发现C语言功底到底是提升了(虽说算法功底至今还木有). #include <iostream> #include <cstdio> #include <cstdlib> #include <cstri…
又见面了,还是原来的配方,还是熟悉的DP....直接秒了... The Cow Lexicon Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 7316 Accepted: 3421 Description Few know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words, each containing no more 25 of the…
http://poj.org/problem?id=3267 The Cow Lexicon Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9380   Accepted: 4469 Description Few know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words, each containing no more 25 of t…
The Cow Lexicon Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 8815 Accepted: 4162 Description Few know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words, each containing no more 25 of the characters 'a'..'z'. Their cowmu…
The Cow Lexicon Time Limit : 4000/2000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 16   Accepted Submission(s) : 10 Problem Description Few know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words,…
The Cow Lexicon Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 8211   Accepted: 3864 Description Few know that the cows have their own dictionary with W (1 ≤ W ≤ 600) words, each containing no more 25 of the characters 'a'..'z'. Their c…