Paratroopers Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7881 Accepted: 2373 Description It is year 2500 A.D. and there is a terrible war between the forces of the Earth and the Mars. Recently, the commanders of the Earth are informed…

                                                 Paratroopers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8443   Accepted: 2541 Description It is year 2500 A.D. and there is a terrible war between the forces of the Earth and the Mars…

Description It is year 2500 A.D. and there is a terrible war between the forces of the Earth and the Mars. Recently, the commanders of the Earth are informed by their spies that the invaders of Mars want to land some paratroopers in them× n grid yard…

伞兵(Paratroopers) 时间限制: 1 Sec  内存限制: 128 MB 题目描述 公元 2500 年,地球和火星之间爆发了一场战争.最近,地球军队指挥官获悉火星入侵者将派一些伞兵来摧毁地球的兵工厂,兵工厂是一个 m×n 大小的网格.他还获悉每个伞兵将着陆的具体位置(行和列).由于火星的伞兵个个都很强壮.而且组织性强,只要有一个伞兵存活了,就能摧毁整个兵工厂.因此,地球军队必须在伞兵着陆后瞬间全部杀死他们. 为了完成这个任务,地球军队需要利用高科技激光枪.他们能在某行(或某列)安装一…

Paratroopers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7267   Accepted: 2194 Description It is year 2500 A.D. and there is a terrible war between the forces of the Earth and the Mars. Recently, the commanders of the Earth are infor…

http://poj.org/problem?id=3308 r*c的地图 每一个大炮可以消灭一行一列的敌人 安装消灭第i行的大炮花费是ri 安装消灭第j行的大炮花费是ci 已知敌人坐标,同时消灭所有敌人,问最小花费 花费为所有大炮消费的乘积 乘转加:log(a*b*c)=log(a)+log(b)+log(c) 经典的最小点权覆盖 源点向行连,列向汇点连 第i行j列有敌人,点i向点j连inf边 最小点权覆盖=最小割 #include<cmath> #include<queue>…

Description It is year 2500 A.D. and there is a terrible war between the forces of the Earth and the Mars. Recently, the commanders of the Earth are informed by their spies that the invaders of Mars want to land some paratroopers in the m × n grid ya…

Description It is year 2500 A.D. and there is a terrible war between the forces of the Earth and the Mars. Recently, the commanders of the Earth are informed by their spies that the invaders of Mars want to land some paratroopers in the m × n grid ya…

Paratroopers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8954   Accepted: 2702 Description It is year 2500 A.D. and there is a terrible war between the forces of the Earth and the Mars. Recently, the commanders of the Earth are infor…

1.这道题学了个单词,product 还有 乘积 的意思.. 题意就是在一个 m*n的矩阵中,放入L个敌军的伞兵,而我军要在伞兵落地的瞬间将其消灭.现在我军用一种激光枪组建一个防御系统,这种枪可以安装在一行(或者一列),并且安装在不同行(或者不同列)的费用是不一样的,枪的攻击范围是一行(或者一列).安装所有枪的费用是它们每个费用的“乘积”,现在求组建这个系统需要的最小费用. 2.与前面做的二分图的一道题有点相似(POJ - 3041 Asteroids(最小点覆盖数)).但是现在这道题在不同行(…