http://acm.hdu.edu.cn/showproblem.php?pid=2817 __int64 pow_mod (__int64 a, __int64 n, __int64 m)快速幂取模函数. A sequence of numbers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4047    Accepted Su…

A sequence of numbers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4550    Accepted Submission(s): 1444 Problem Description Xinlv wrote some sequences on the paper a long time ago, they might…

Problem Description Xinlv wrote some sequences on the paper a long time ago, they might be arithmetic or geometric sequences. The numbers are not very clear now, and only the first three numbers of each sequence are recognizable. Xinlv wants to know…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2817 题目大意:给出三个数,来判断是等差还是等比数列,再输入一个n,来计算第n个数的值. #include <iostream> #include <cstdio> #include <cmath> #define m 200907 using namespace std; __int64 fun(__int64 j,__int64 k) { __int64 s=; whi…

A sequence of numbers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4384    Accepted Submission(s): 1374 Problem Description Xinlv wrote some sequences on the paper a long time ago, they might…

题目连接  http://acm.hdu.edu.cn/showproblem.php?pid=2817 题意: 给定三个数,判断是等差数列还是等比数列,然后输出第k项. 做法:直接判断即可 #include <iostream> #include <cstdio> #include <algorithm> #include <vector> #include <set> #include <queue> #include <s…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2817 解题思路:arithmetic or geometric sequences 是等差数列和等比数列的意思, 即令输入的第一个数为a(1),那么对于等差数列 a(k)=a(1)+(k-1)*d,即只需要求出 a(k)%mod   又因为考虑到k和a的范围, 所以对上式通过同余作一个变形:即求出 (a(1)%mod+(k-1)%mod*(d%mod))%mod 对于等比数列 a(k)=a(1)*q…

HDU 1711 Number Sequence(数列) Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) [Description] [题目描述] Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N…

HDU 1711 Number Sequence (字符串匹配,KMP算法) Description Given two sequences of numbers : a1, a2, ...... , aN, and b1, b2, ...... , bM (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make aK = b1, aK+1 = b2, ...... , aK+M…

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