Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh! now here is the real onsite task for Harry. You are given a magrid S ( a magic grid ) having…

Magic Grid Time Limit:336MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Description Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh!…

C. Magic Grid time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Let us define a magic grid to be a square matrix of integers of size n×nn×n, satisfying the following conditions. All integers…

E. Magic Stones 链接 题意: 给定两个数组,每次可以对一个数组选一个位置i($2 \leq i \leq n - 1$),让a[i]=a[i-1]+a[i+1]-a[i],或者b[i]=b[i-1]+b[i+1]-b[i].问进行一些操作后,a和b能否相同. 分析: 考虑一次操作会变成什么样子. a b c a a+c-b c 我们发现这些数字差分后是不变的.于是对两个数组差分后,排序,看是否一样即可.注意判一下1和n是否相等. 代码: #include<cstdio> #in…

在MagicCombo组件中嵌入Grid,以支持分页查找和跨页选取 ​ 1. ​2. [代码][JavaScript]单选示例代码     <script type="text/javascript" src="/js/mac/pager.js"></script><script type="text/javascript" src="/js/mac/grid.js"></script…

题目 大意:构造一个n行n列的矩阵,使得每一行,每一列的异或和都相等,n是4的倍数. 先看4*4的矩阵,我们很容易构造出符合要求的矩阵,比如 0    1    2    3 4    5    6    7 8    9   10  11 12 13  14  15 这个矩阵每行每列的异或和都为0 对于一个n*n的矩阵,我们可以写成多个4*4的矩阵,为了保证数字不重复,可以对于其他的小矩阵都加上16,32等等 #include<iostream> #include<cstdio>…

题目大意 给你一个n 让你用0~n^2-1的数填满一个n*n的正方形 满足每个数值出现一次且每行每列的异或值相等 输出任意一种方案 分析 我们发现对于4*4的正方形 0  1  2  3 4  5  6  7 8  9 10 11 12 13 14 15 是满足条件的 那么如果对正方形中的每一个数都加上一个相同的数 那么这个正方形一定还是满足的 由于这种构造方式的异或值均是0 所以任意多个满足的正方形拼起来一定也是满足的 于是我们将正方形分为若干4*4的正方形 使得每一个正方形是一组连续的数 那…

目录 \(\bf {Round \ \#500 \ (Div. \ 1)}\) \(\bf {Round \ \#589 \ (Div. \ 2)}\) \(\bf {Avito \ Cool \ Challenge \ 2018}\) \(\bf {Round \ \#545 \ (Div. \ 1)}\) \(\bf {Round \ \#454 \ (Div. \ 1)}\) \(\bf {Round \ \#575 \ (Div. \ 3)}\) \(\bf Codefest \ 19\…

CF 1110 D. Jongmah 题目大意:给你​\(n\)个瓷砖,每块瓷砖上有一个数字​\(a_i,(1\leq a_i\leq m)\).你可以将三个有连续数字​\((比如3,4,5)\)的瓷砖或者三个数字相同​\((比如7,7,7)\)的瓷砖组成一个三元组.每个瓷砖只能用一次.问最多可以得到多少个三元组.​ 比赛的时候好像全场A穿,然而并没有想到 (TAT. 一开始想到\(DP\),但是​觉得状态数太大:于是想了奇奇怪怪的贪心,但是都能找到反例. 这道题的关键是要发现一个性质:同一位置…

B. Chris and Magic Square 题目连接: http://www.codeforces.com/contest/711/problem/B Description ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with integers. Chris notice…

ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with integers. Chris noticed that exactly one of the cells in the grid is empty, and to enter Udayland, they need to fi…

time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output   ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with in…

Chris and Magic Square 题目链接: http://codeforces.com/contest/711/problem/B Description ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with integers. Chris noticed that…

A ZS the Coder and Chris the Baboon are travelling to Udayland! To get there, they have to get on the special IOI bus. The IOI bus has nrows of seats. There are 4 seats in each row, and the seats are separated into pairs by a walkway. When ZS and Chr…

A. Bus to Udayland time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output ZS the Coder and Chris the Baboon are travelling to Udayland! To get there, they have to get on the special IOI bus. The…

2019-01-18 4543: [POI2014]Hotel加强版:长链剖分+树形dp. 3653: 谈笑风生:dfs序+主席树. POJ 3678 Katu Puzzle:2-sat问题,给n个变量赋值(0/1),满足所有等式. POJ 3683 Priest John's Busiest Day:2-sat问题,输出方案. 2019-01-19 1997: [Hnoi2010]Planar:2-sat问题,存在哈密顿路径的图判断是否是平面图. 3495: PA2010 Riddle:2-s…

Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh! now here is the real onsite task for Harry. You are given a magrid S ( a magic grid ) having…

A Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh! now here is the real onsite task for Harry. You are given a magrid S ( a magic grid ) havin…

这套题还是有点质量的吧 -- 题目链接 A. XORinacci 傻叉签到题,因为异或的性质所以这个序列的循环节长度只有 \(3\) -- 查看代码 B. Uniqueness 因为序列长度乃至数的种类都不超过 \(2000\),考虑先把序列离散化. 题意让我们求一个最短的区间满足如下性质,对于每一种数,其在此区间出现次数不小于在原序列中的出现次数减 \(1\). 可以先前缀和求一下对于每种数,当前位置及之前的出现次数,和至少一共需要删掉多少个这种数,即在原序列中的出现次数减 \(1\),方便以…

目录 Contest Info Solutions A. XORinacci B. Uniqueness C. Magic Grid D. Restore Permutation E. Let Them Slide F. Bits And Pieces Contest Info Practice Link Solved A B C D E F G H 6/8 O O Ø O O Ø - - O 在比赛中通过 Ø 赛后通过 ! 尝试了但是失败了 - 没有尝试 Solutions A. XORina…

蒟蒻的心路历程 上来看B,结果不会... 回来做A,写完之后nantf已经切B了. 回来做B,花了13min磕了出来. 继续做C,自闭. 继续做D,花了10min磕了出来. 继续做E,一开始有点自闭,后来口胡了出来,但是实现略微死人,花了1h磕了出来. 继续自闭....... A XORinacci \(a,b,a\oplus b,a,b,a\oplus b,\ldots\) B Uniqueless 使用two-pointer, 前缀和优化后判断\(O(n)\),时间复杂度\(O(n^2)\)…

传送门 A. XORinacci 手玩三四项发现序列就是 $a,b,a\ xor\ b,a,b,...$,直接输出即可 #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<cmath> using namespace std; typedef long long ll; inline int read() { ,f=; char ch…

Codefest 19 (open for everyone, rated, Div. 1 + Div. 2) C. Magic Grid 这种题直接构造 数n是2的n次方的倍数的时候可以这样划分数 比如n是4的倍数  n=k*4 000        001         010         011 100        101         110         111 (k-1)00   (k-1)01   (k-1)10   (k-1)11 然后填格子 Codeforces R…

传送门 A. XORinacci 签到. Code /* * Author: heyuhhh * Created Time: 2020/2/26 9:26:33 */ #include <iostream> #include <algorithm> #include <cstring> #include <vector> #include <cmath> #include <set> #include <map> #inc…

A 3 x 3 magic square is a 3 x 3 grid filled with distinct numbers from 1 to 9 such that each row, column, and both diagonals all have the same sum. Given an grid of integers, how many 3 x 3 "magic square" subgrids are there?  (Each subgrid is co…

A 3 x 3 magic square is a 3 x 3 grid filled with distinct numbers from 1 to 9 such that each row, column, and both diagonals all have the same sum. Given an grid of integers, how many 3 x 3 "magic square" subgrids are there?  (Each subgrid is co…

开头 这是每周比赛中的第一道题,博主试了好几次坑后才勉强做对了,第二道题写的差不多结果去试时结果比赛已经已经结束了(尴尬),所以今天只记录第一道题吧 题目原文 Magic Squares In Grid A 3 x 3 magic square is a 3 x 3 grid filled with distinct numbers from 1 to 9 such that each row, column, and both diagonals all have the same sum.…

problem 840. Magic Squares In Grid solution: class Solution { public: int numMagicSquaresInside(vector<vector<int>>& grid) { ].size(); ; ; i<m-; ++i) { ; j<n-; ++j) { if(isvalid(grid, i, j)) cnt++; } } return cnt; } bool isvalid(vect…

LINK:Kaavi and Magic Spell 一打CF才知道自己原来这么菜 这题完全没想到. 可以发现 如果dp f[i][j]表示前i个字符匹配T的前j个字符的方案数 此时转移变得异常麻烦 状态转移一次变成了O(n). 会超时 而且这个状态的转移也是不正确的 可能当前的S字符串后面放了一些不能匹配的东西 但是此时却体现不出来. 那我们如何描述每次增加一个字符且和T匹配多少这种状态呢. 一个思路 先对于S串的某个i暴力枚举 其对应在T中的位置 这样的话dp就变成了 f[i][j][k]表…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3752 访问. 3 x 3 的幻方是一个填充有从 1 到 9 的不同数字的 3 x 3 矩阵,其中每行,每列以及两条对角线上的各数之和都相等. 给定一个由整数组成的 m * n 矩阵,其中有多少个 3 × 3 的 "幻方" 子矩阵?(每个子矩阵都是连续的). 输入: [[4,3,8,4],       [9,5,1,9],       [2,7,6,2]…