CF luogu 先讲两个靠谱的做法 1.首先因为有n个点,m条不存在的边,所以至少存在一个点,和m/n个点之间没边,所以把这个点找出来,连一下其他相连的点,这样还剩m/n个点没确定在哪个联通块,而这些点最多和n-1个点有边,所以从这些点暴力合并即可 2.开一个队列/set/链表维护没有确定在哪个联通块的边,每次先取出一个点,然后往点集里尽量连边,再把连出的点放到队列里继续连边合并,这样每次都能搜出一个联通块 下面是假算法 每次找一个没标记的点,打标记,爆枚所有存在的边,和对应点连上,在把刚刚扫…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0          3 |          | 1 --- 2    4 Given n = 5 and…

Write a program to find the strongly connected components in a digraph. Format of functions: void StronglyConnectedComponents( Graph G, void (*visit)(Vertex V) ); where Graph is defined as the following: typedef struct VNode *PtrToVNode; struct VNode…

原题链接在这里:https://leetcode.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected com…

We will learn how to use withRouter() to inject params provided by React Router into connected components deep in the tree without passing them down all the way down as props. The app component itself does not really use filter. It just passes the fi…

Number of Connected Components in an Undirected Graph Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1:…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0          3 |          | 1 --- 2    4 Given n = 5 and…

E - Connected Components? 思路: 补图bfs,将未访问的点存进set里 代码: #include<bits/stdc++.h> using namespace std; #define ll long long #define pb push_back #define mem(a,b) memset(a,b,sizeof(a)) ; bool vis[N]; int head[N]; int a[N]; ,ans=; struct edge{ int to,next;…

Write a function to count the number of connected components in a given graph. Format of functions: int CountConnectedComponents( LGraph Graph ); where LGraph is defined as the following: typedef struct AdjVNode *PtrToAdjVNode; struct AdjVNode{ Verte…

［抄题］: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: Input: n = 5 and edges = [[0, 1], [1, 2], [3, 4]…

原题链接在这里:https://leetcode.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected com…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: Input: n = 5 and edges = [[0, 1], [1, 2], [3, 4]] 0 3…

E. Connected Components? time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given an undirected graph consisting of n vertices and  edges. Instead of giving you the edges that exist i…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: | | --- Given n = 5 and edges = [[0, 1], [1, 2], [3, 4…

Discription You are given an undirected graph consisting of n vertices and  edges. Instead of giving you the edges that exist in the graph, we give you m unordered pairs (x, y) such that there is no edge between x and y, and if some pair of vertices…

spark最新版公布了.之前的版本号就已经集成了graphx,这个版本号还改了一些bug. 我做了简单測试,只是网上关于集群模式执行spark资料太少了,仅仅有关于EC2(见參考资料1)的.可是还非常旧,好多命令都有变化了.非常讨厌写安装类的博客不注明当前使用软件的版本号,这是常识好不好?! 我的平台配置: spark:0.9.1 scala:2.10.4 hadoop:1.0.4 jdk:1.7.0 master node:1 worker node:16 1. spark 0\.9\.1的部…

We already know of the large corporation where Polycarpus works as a system administrator. The computer network there consists of n computers and m cables that connect some pairs of computers. In other words, the computer network can be represented a…

E. Connected Components? You are given an undirected graph consisting of n vertices and edges. Instead of giving you the edges that exist in the graph, we give you m unordered pairs (x, y) such that there is no edge between x and y, and if some pair…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0        3 |          | 1 --- 2    4 Given n = 5 and e…

292D - Connected Components D. Connected Components time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output We already know of the large corporation where Polycarpus works as a system administrato…

D. Connected Components 题意 现在有n个点,m条编号为1-m的无向边,给出k个询问,每个询问给出区间[l,r],让输出删除标号为l-r的边后还有几个连通块? 思路 去除编号为[l,r]的边后,只剩下了[1,l-1]&&[r+1,m]两部分. 我们维护一个前缀以及后缀并查集,询问的时候把这两部分的边合并一下,就可以求出连通块的个数. 精辟! 代码 #include<bits/stdc++.h> #include<vector> #include…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 并查集 日期 题目地址:https://leetcode-cn.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目描述 Given n nodes labeled from 0 to n - 1 and a list of undirected edges (ea…

算连接的..那就是union find了 public class Solution { public int countComponents(int n, int[][] edges) { if(edges.length == 0) return n; int[] nodes = new int[n]; for(int i = 0; i < n;i++) nodes[i] = i; for(int i = 0; i < edges.length;i++) { int a = search(n…

题意:求图中的连通块数,注意孤立的算自连通! 例如:6个顶点3条路径,其中路径为:1->2    4->5  1->3 那么有(1-2&&1->3) + (4->5) + (6) 共3个连通块! 解法:对每个节点宽搜! #include<iostream> #include<memory.h> #include<queue> using namespace std; ][]; ]; int N,M; int main(){…

#include <algorithm> #include <cstdio> #include <iostream> #include <queue> #include <set> using namespace std; const int N = 2e5 + 5; vector<int> result; std::set<pair<int, int> > unExistedMap; int nextPoin…

Description 题库链接 给你一个 \(n\) 个点 \(m\) 条边的无向图,求其补图的连通块个数及各个连通块大小. \(1\leq n,m\leq 200000\) Solution 参考了 ww140142 的做法.题解也转自该博客. 每次枚举一个未处理过的点,然后从它开始宽搜出它所在的连通块: 具体是枚举它的所有原图的边,标记起来,枚举边之后再枚举所有的点,将未标记的点加入该连通块,并加入队列继续宽搜: 为了节约无用的枚举,我们还需要对所有点构建链表,将已经在某个块内的点删除:…

拓扑排列可以指明除了循环以外的所有指向,当反过来还有路可以走的话,说明有刚刚没算的循环路线,所以反过来能形成的所有树都是循环…

大意:给定无向图, 求补图的连通块数 bfs模拟即可, 这里用了map存图, set维护未划分的点集, 复杂度$O(nlog^2n)$, 用链表的话可以$O(n)$ #include <iostream> #include <algorithm> #include <cstdio> #include <set> #include <map> #include <queue> #define REP(i,a,n) for(int i=a…

题目链接:https://cn.vjudge.net/contest/275589#problem/F 题目大意:就是给你n个数,如果说两个数之间的gcd!=1,那么就将这两个点连起来,问你最终这些点能形成几块 具体思路:首先,我们可以讲所有数的倍数给标记出来,然后如果有一个数是 6,我们就把2 3 6 全部指向6,这样的话,每当我们找到一个数,我们就把这个数和他的素因子连起来(并查集),往小的地方连,然后最后看一下输入的n个数是不是标记的自己,如果是自己那么这肯定是一个块,如果不是标记的自己,…

一.题目 二.题目链接 http://codeforces.com/contest/920/problem/E 三.题意 给定一个$N$和$M$.$N$表示有$N$个点,$M$表示,在一个$N$个点组成的无向完全图中,接下来的$M$条无向边不存在. 问你在这个图中有多少个连通分量,并且从小到大输出每个连通分量的顶点个数. 四.思路 求无向图的连通分量个数,只需要跑一边bfs就OK了.其实dfs也可以,只是太多的“函数压栈现场保护”浪费一丢丢时间而已,慢一点点,影响其实并不大. 要注意的是,无论跑…