leetcode: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

题目简述 Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spac…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

题目描述: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spa…

题目: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

[ 问题: ] Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. 给你一个字符串,设法获取它最后一个单词的长度.假设这个单词不存在,则返回0. [ 分析 : ] A word is defined…

这个题目很简单,给一个字符串,然后返回最后一个单词的长度就行.题目如下: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a charact…

Length of Last Word  Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence cons…

扫描每个WORD的长度并记录即可. int lengthOfLast(const char *s) { //扫描统计每个word的长度 ; while (*s) { if (*s++ != ' ')//注意不管是否满足s都要++ len++; else if (*s && *s != ' ') len = ; } return len; }…

1. 原题链接 https://leetcode.com/problems/length-of-last-word/description/ 2. 题目要求 给定一个String类型的字符串,字符串中可能含有空格‘  ’.从字符串的末尾开始查找,找到第一个单词,该单词中间不能有空格,并返回其长度. 3. 解题思路 首先判断该字符串是否为空,为空直接返回 0: 否则,从尾部向前查找,使用两个while循环,第一个while循环用于过滤空格,当该位置不为空格时,跳出while循环: 然后进入第二个w…

题目: 输入字符串 s,返回其最后一个单词的长度 如 s="Hello World"   返回5 s="Hello World    "   返回5 s="  "     返回0 开始从前向后判断,超时了.改成从后向前判断,通过了. class Solution { public: int lengthOfLastWord(const char *s) { ; int slen = strlen(s); ; i >= ; i--) { if…

https://leetcode.com/problems/length-of-last-word/ int lengthOfLastWord(char* s) { int ans = 0; int fans = 0; for(int i = 0;s[i];i++){ if (s[i] ==' '){fans = ans;ans = 0;while(s[i + 1] == ' '){i++;}} else ans++; } return ans?ans:fans; }…

找出最后一个词的长度 class Solution { public: int lengthOfLastWord(string s) { , l = , b = ; while((b = s.find(" ", a)) != string::npos){ ) l = b - a; a = b + ; } if(a == s.size()) return l; else return s.size() - a; } };…

做法很巧妙.分成左右两个对应的部分,遇到左半部分则入栈,遇到右半部分则判断对应的左半部分是否在栈顶.注意最后要判断堆栈是否为空. bool isValid(const string& s) { string left = "([{"; string right = ")]}"; stack<char> stk; for (auto c : s) { if (left.find(c) != string::npos) { stk.push(c);…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

一天一道LeetCode系列 (一)题目 Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence cons…

原题地址:https://oj.leetcode.com/problems/length-of-last-word/ 题意: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A wo…

https://leetcode.com/problems/length-of-last-word/ 题目: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is de…

LeetCode第58题: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 库函数 双指针 单指针 日期 题目地址:https://leetcode.com/problems/length-of-last-word/description/ 题目描述 Given a string s consists of upper/lower-case alphabets and empty space characters ' ',…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Length of Last Word Total Accepted: 47690 Total Submissions: 168587     Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. N…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…