HDU 6373 Pinball】的更多相关文章

6373.Pinball 物理受力分析题目. 画的有点丑,通过受力分析,先求出θ角,为arctan(b/a),就是atan(b/a),然后将重力加速度分解为垂直斜面的和平行斜面的,垂直斜面的记为a1,平行斜面的记为a2. a1=g*sinθ,a2=g*cosθ,然后算出小球到斜面的侧面高度h,以及小球到斜面底部的距离l,小球走h米高度所花费的时间t2为弹一次花费的时间,然后通过ll花费的时间t1为总时间,直接算倍数就是答案. 具体的代码注释. 代码: //1012-6373-几何-物理题目 #i…
Pinball Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 131    Accepted Submission(s): 55 Problem Description There is a slope on the 2D plane. The lowest point of the slope is at the origin.…
hdu 5618 Jam's problem again #include <bits/stdc++.h> #define MAXN 100010 using namespace std; int n,k,T,xx; int ans[MAXN],c[MAXN],f[MAXN]; struct Node{ int x,y,z,id; }a[100010],b[100010]; inline int read(){ char ch; bool f=false; int res=0; while (…
Pinball Game 3D Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1137    Accepted Submission(s): 477 Problem Description RD is a smart boy and excel in pinball game. However, playing common 2D…
Pinball Game 3D Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 688    Accepted Submission(s): 276 Problem Description RD is a smart boy and excel in pinball game. However, playing common 2D p…
离散化x然后用树状数组解决,排序y然后分治解决,z在分治的时候排序解决. 具体:先对y排序,solve(l,r)分成solve(l,mid),solve(mid+1,r), 然后因为是按照y排序,所以l,mid区间内的y值都小于mid+1,r.现在再对z排序,按照顺序以x做关键字插入到树状数组中,那么就可以一起解决l,mid对mid+1,r的影响. #include <iostream> #include <cstdio> #include <cstring> #inc…
题意是给定两个点的位置,过原点引一条射线穿过第一个点,射线位置作为斜面位置,第二个点处令一小球自由落体,问小球能碰撞到斜面几次. 开始时想算出两次碰撞中小球沿斜面运动的距离,然后发现每一段距离会因为高度差导致动能不断变大,然后一脸懵...... 直到看了别人的题解,才想起运动分解来(这可是高中基础知识,罪过). 将小球受到的重力在平行于斜面和垂直于斜面方向分解,小球在平行于斜面方向做初速度为0的匀加速直线运动,在垂直于斜面方向做类自由落体(初速度为0的匀加速直线)运动,由于能量不会因碰撞而损耗,…
题意 给定一个斜面,从某处让一个小球作自由落体运动,求小球与斜面的碰撞次数(假设都为弹性碰撞). 分析 题图如下,x轴.y轴是虚拟的. 根据高中物理的套路,沿斜面方向分解重力加速度即可. #include<bits/stdc++.h> using namespace std; const double g = 9.8; const double EXP = 0.000001; double a, b, x, y; int main() { int T; scanf("%d"…
Pinball Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 568    Accepted Submission(s): 244 Problem Description There is a slope on the 2D plane. The lowest point of the slope is at the origin.…
Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194    Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的.  一天,当他正在苦思冥想解困良策的…