http://acm.hdu.edu.cn/showproblem.php?pid=5012 Problem Description There are 2 special dices on the table. On each face of the dice, a distinct number was written. Consider a1.a2,a3,a4,a5,a6 to be numbers written on top face, bottom face, left face,…

You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move diagonal…

BFS模板,记住这5个: (1)针对树的BFS 1.1 无需分层遍历 from collections import deque def levelOrderTree(root): if not root: return q = deque([root]) while q: head = q.popleft() do something with this head node... if head.left: q.append(head.left) if head.right: q.append…

//标准的层次遍历模板 //居然因为一个j写成了i,debug半天.....解题前一定要把结构和逻辑想清楚,不能着急动手,理解清楚题意,把处理流程理清楚再动手,恍恍惚惚的写出来自己慢慢debug吧 #include<cstdio>#include<vector>#include<queue>#include<algorithm>using namespace std;const int maxn=1001;struct node{ int level; ve…

转自:欣哥 下面是bfs一般的形式,谈不上模板但一般都这么来做有点乱有什么多交流 bfs一般用于求最短时间 #include<stdio.h>#include<queue>using namespace std; 上面是头文件定义 struct stu 开两个结构体abc,xyz,一般都开两个{ int x; int y; int t;}abc,xyz; queue<struct stu> p; 定义一个struct stu型STL队列 int dir[4][2]={{…

关于图的遍历,通常有深度优先搜索(DFS)和广度优先搜索(BFS),本文结合一般的图结构(邻接矩阵和邻接表),给出两种遍历算法的模板 1.深度优先搜索(DFS) #include<iostream> #include<unordered_map> #include<queue> #include<cstring> #include<cstdlib> #include<cmath> #include<algorithm> #…

Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16748   Accepted: 6522 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled…

题目链接:http://icpc.njust.edu.cn/Problem/Hdu/1242/ 这次的迷宫是有守卫的,杀死一个守卫需要花费1个单位的时间,所以以走的步数为深度,在每一层进行搜索,由于走一步的花费不一定是1,所以我们需要用优先队列寻找最优值.这个题目真是模板题. 代码如下: #include<bits/stdc++.h> using namespace std; typedef unsigned int ui; typedef long long ll; typedef unsi…

/* 题意:就是给定两个筛子,每个筛子上6个面,每个面的数字属于[1,6], 且互不相同! 问a筛子最少经过按照题目规定的要求转动,达到和b筛子上下左右前后的数字相同! 思路:很直白的bfs,将每一种状态对应一个数字,保证这种状态不会重新加入队列中! */ #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<queue> using…

#include<bits/stdc++.h>///该头文件为万能头文件,有些学校oj不能使用,读者可根据需要自行修改 using namespace std; ; int vis[MAXN][MAXN]; ]={,-,-,-,-,,,,}; ]={,-,-,,,,,-,-}; struct point { int x; int y,step; }; queue<point>q; int xx1,yy1,x2,y2; int res; void bfs() { vis[xx1][y…