Problem Description As we know , we always use the decimal system in our common life, even using the computer. If we want to calculate the value that 3 plus 9, we just import 3 and 9.after calculation of computer, we will get the result of 12. But af…

#include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define maxn 1000 using namespace std; char str[maxn]; int change(char *s) { int k=strlen(s); int pos; ; ; i<k; i++) { if(s[i]=='(') { pos=i; break; } }…

题意:给你n个r进制数,让你求和. 析:思路就是先转化成十进制,再加和. 代码如下: #include <iostream> #include <cstdio> #include <algorithm> #include <queue> #include <vector> #include <cstring> #include <map> using namespace std; const int maxn = 70;…

一,十进制(decimal system)转换函数说明 1,十进制转二进制 decbin() 函数,如下实例 echo decbin(12); //输出 1100 echo decbin(26); //输出 11010 decbin (PHP 3, PHP 4, PHP 5) decbin -- 十进制转换为二进制 说明 string decbin ( int number ) 返回一字符串,包含有给定 number 参数的二进制表示.所能转换的最大数值为十进制的 4294967295,其结果为…

#include <iostream> #include <cmath> #include <string.h> using namespace std; int main() { int sum,m,len,t,i,k,s; char a[1001]; while(cin>>t) { sum=0; while(t--) { cin>>a; m=0; len=strlen(a); for(i=0;i<len;i++) {if(a[i]=='…

Problem Description As we know , we always use the decimal system in our common life, even using the computer. If we want to calculate the value that 3 plus 9, we just import 3 and 9.after calculation of computer, we will get the result of 12.But aft…

http://acm.hdu.edu.cn/game/entry/problem/list.php?chapterid=1§ionid=2 1.2.5 #include<stdio.h> /* 题意:找闰年. if((i%4==0 && i%100!=0) || i%400==0)count++; 3 2005 25 1855 12 2004 10000 2108 1904 43236 */ int main() { int t,y,n; int i,count=0; whil…

Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 982    Accepted Submission(s): 440 Problem Description After a day, ALPCs finally complete their ultimate intelligence system,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1690 Bus System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6569    Accepted Submission(s): 1692 Problem Description Because of the huge popula…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4744 题意:三维空间n个点,每个点有一个wi值.每对点的距离定义为floor(欧拉距离),每对点之间建一条边的费用为两点间的距离,每对点之间可以建多条边.现要求对每一个点 i ,都在wi 个简单环上(每个点每条边都只经过一次),每条边只能属于一个简单环,简单环的费用为每条边的费用之和,问最小的建环费用. 思路:每个点拆成a.b两个点,从附加源点S到a连一条边,容量为wi,费用为0:从b到附加汇点T连…

//package Main; import java.util.Scanner; public class Main { static int [][] mat=new int [2][2]; static int [][] unit=new int [2][2]; static int [][] as=new int [2][2]; //static Solve ans; static int a,b,n; static int mod=7; public static void main(…

Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3414    Accepted Submission(s): 1494 Problem Description After a day, ALPCs finally complete their ultimate intelligence syste…

Intelligence System Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 2   Accepted Submission(s) : 1 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description After a day, ALPCs…

http://acm.hdu.edu.cn/showproblem.php?pid=2160 Problem Description 话说现在猪肉价格这么贵,著名的ACBoy 0068 也开始了养猪生活.说来也奇怪,他养的猪一出生第二天开始就能每天中午生一只小猪,而且生下来的竟然都是母猪.不过光生小猪也不行,0068采用了一个很奇特的办法来管理他的养猪场:对于每头刚出生的小猪,在他生下第二头小猪后立马被杀掉,卖到超市里.假设在创业的第一天,0068只买了一头刚出生的小猪,请问,在第N天晚上,00…

Problem Description Because of the huge population of China, public transportation is very important. Bus is an important transportation method in traditional public transportation system. And it's still playing an important role even now. The bus sy…

Bus System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6082    Accepted Submission(s): 1560 Problem Description Because of the huge population of China, public transportation is very importa…

Description At the end of the 200013 th year of the Galaxy era, the war between Carbon-based lives and Silicon civilization finally comes to its end with the Civil Union born from the ruins. The shadow fades away, and the new-born Union is opening a…

Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2909    Accepted Submission(s): 1259 Problem Description After a day, ALPCs finally complete their ultimate intelligence syst…

题目大意:给出若干巴士不同价格的票的乘坐距离范围,现在有N个站点,有M次询问,查询任意两个站点的最小花费 解析:由于是多次查询不同站点的最小花费,所以用弗洛伊德求解 时间复杂度(O^3) 比较基础的弗洛伊德 #include <iostream> #include <cstdio> #include <cstring> using namespace std; #define INF 1000000000000 typedef __int64 LL; ; __int64…

前几天正看着网络流,也正研究着一个有上下界的网络流的问题,查看了很多博客,觉得下面这篇概括的还是相当精确的: http://blog.csdn.net/leolin_/article/details/7208246 里面包含了其中一些解释.看了这道题的题解之后就会发现确实好像就是一个无源的有上下界的可行流. #pragma warning(disable:4996) #include <iostream> #include <cstring> #include <string…

题意: 给出一个N个节点的有向图.图中任意两点进行通信的代价为路径上的边权和.如果两个点能互相到达那么代价为0.问从点0开始向其余所有点通信的最小代价和.保证能向所有点通信. 题解: 求出所有的强连通分量,然后进行缩点操作.最后贪心的找出每个点的最小代价,然后求和. #include <iostream> #include <cstdio> #include <vector> #include <cstring> #include <algorithm…

http://www.cnblogs.com/yellowapplemylove/archive/2011/08/23/2150316.html 一直很奇怪C#的预定义数据类型中为什么加了一个decimal,有float和double不就够了吗?今天来挖一挖. 浮点型 Name CTS Type De script ion Significant Figures Range (approximate) float System.Single 32-bit single-precision flo…

注意:有效位:小数点前后的全部数字,不包括小数点在内 float:浮点型,含字节数为4,32bit,数值范围为-3.4E38~3.4E38(7个有效位) double:双精度实型,含字节数为8,64bit数值范围-1.7E308~1.7E308(15个有效位) decimal:数字型,128bit,不存在精度损失,常用于银行帐目计算.(28个有效位) float f = 345.98756f;//结果显示为345.9876,只显示7个有效位,对最后一位数四舍五入. double d=345.97…

先标注一个音标,因为我老是读错:decimal ['desɪml] 精度对比: 类型 CTS 类型 描述 有效数字 范围 float System.Single 32-bit single-precision floating point 7 ±1.5 × 10−45 to ±3.4 × 1038 double System.Double 64-bit double-precision floating point 15/16 ±5.0 × 10 −324 to ±1.7 × 10308 dec…

System.Data.DbType 与其它DbType的映射关系 有如下类型的映射对照: System.Data.SqlClient.SqlDbType System.Data.OleDb.OleDbType System.Data.Odbc.OdbcType System.Data.OracleClient.OracleType 格式: DbType.枚举名(枚举值) = DbType.枚举名(枚举值) =========== System.Data.SqlClient.SqlDbType…

知识点: 1.System.Math.PI 2.System.Math.Truncate() //取整 问题: 需要找出一个decimal 或 double数的整数部分. 解决方案 只要将一个decimal 或 double 数截断为最接近于0的数,就可以得到其整数部分.为此,可以使用重载的静态System.Math.Truncate方法,这个方法取一个decimal或一个double作为参数,并返回同样的类型. using System; using System.Collections.Ge…

Description Usually we use number in the decimal system, for it is so convenient for us to remember and calculate. But it is not the same in the computer world where numbers are always stored in the binary system. For example, the number 21 in decima…

有如下类型的映射对照: System.Data.SqlClient.SqlDbType  System.Data.OleDb.OleDbType System.Data.Odbc.OdbcType System.Data.OracleClient.OracleType 格式: DbType.枚举名(枚举值) = DbType.枚举名(枚举值) =========== System.Data.SqlClient.SqlDbType ========= System.Data.SqlClient.S…

浮点型 Name CTS Type Description Significant Figures Range (approximate) float System.Single 32-bit single-precision floating point 7 ±1.5 × 10?45 to ±3.4 × 1038 double System.Double 64-bit double-precision floating point 15/16 ±5.0 × 10 ?324 to ±1.7 ×…

一直很奇怪C#的预定义数据类型中为什么加了一个decimal,有float和double不就够了吗?今天来挖一挖. 浮点型 Name CTS Type De script ion Significant Figures Range (approximate) float System.Single 32-bit single-precision floating point 7 ±1.5 × 10?45 to ±3.4 × 1038 double System.Double 64-bit dou…