On a sunny Sunday, a group of children headed by their teacher came to an amusement park. Aunt Frosya, who was a very kind and quiet person, worked at the ticket window on that day. The teacher gave her the money but didn't say how many tickets she w…

1796. Amusement Park Time limit: 1.0 second Memory limit: 64 MB On a sunny Sunday, a group of children headed by their teacher came to an amusement park. Aunt Frosya,who was a very kind and quiet person, worked at the ticket window on that day. The t…

洛谷 CF1193A Amusement Park 洛谷传送门 题目翻译 有一个游乐场有一个好玩的项目:一些有向滑梯可以将游客从一个景点快速.刺激地传送到另一个景点.现在,你要帮游乐场老板来规划一个造滑梯的项目. 滑梯只能从海拔高的地方向海拔低的地方滑.老板原定的方案已经给出,你的工作是反转某些滑梯的方向(可以反转全部的或一个都不转),并为每个景点指定一个海拔高度,使得每一个滑梯都能下山,那么这个方案是合法的.其成本是要反转的滑梯的总数.对于老板给定的方案,你需要算出所有合法方案的成本总和.由于…

Chinese Girls' Amusement Time Limit: 2000/1000MS (Java/Others)Memory Limit: 128000/64000KB (Java/Others) SubmitStatisticNext Problem Problem Description You must have heard that the Chinese culture is quite different from that of Europe or Russia. So…

Walk Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1142    Accepted Submission(s): 195 Problem Description Biaoge is planning to walk to amusement park. The city he lives can be abstracted as…

鉴于某些原因(主要是懒)就不一题一题写了,代码直接去\(OJ\)上看吧 CodeChef Making Change 传送门 完全没看懂题解在讲什么(一定是因为题解公式打崩的原因才不是曲明英语太差呢--) 由于\(C=\sum x_i\times a_i\),我们可以把\(x_i\)给二进制分解,然后依次考虑每一位 设\(f_{i,j}\)表示考虑到\(C\)的二进制第\(i\)位,且\(0\)到\(i-1\)位都已经对上,进位为\(j\)的方案数,那么考虑所有\(x_i\)当前这一位,每一个\…

武汉科技大学  http://acm.wust.edu.cn/ 华中科技大学 http://acm.hust.edu.cn/vjudge/toIndex.action 杭州电子科技大学  http://acm.hdu.edu.cn/listproblem.php?vol=1 北京大学  http://poj.org/ 浙江大学 http://acm.zju.edu.cn/onlinejudge/showProblemsets.do 湖南大学 http://acm.hnu.cn/ RQNOJ ht…

题目链接 Drazil and Park 中文题面 传送门 如果他选择了x和y,那么他消耗的能量为dx + dx + 1 + ... + dy - 1 + 2 * (hx + hy). 把这个式子写成这个形式 (d1 + d2 + ... + dy - 1 + 2 * hy) + (2 * hx - (d1 + d2 + ... + dx - 1)) 令(2 * hk - (d1 + d2 + ... + dk - 1)) = Lk     (d1 + d2 + ... + dk - 1 + 2…

第三波,走起~~ FFT/NTT复习笔记&多项式&生成函数学习笔记Ⅰ FFT/NTT复习笔记&多项式&生成函数学习笔记Ⅱ 单位根反演 今天打多校时 1002 被卡科技了--赛场上看出来是个单位根反演但不会,所以只好现学这东西了( 首先你得知道单位根是什么东西,对于 \(n\) 次方程 \(x^n-1=0(x\in\mathbb{C})\),在复数域上有 \(n\) 个根,其对应到复平面上就是单位圆的 \(n\) 等分点,我们将这些单位根从 \(x\) 轴正半轴开始顺时针依次…

Dying Light Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 513    Accepted Submission(s): 122 Problem Description LsF is visiting a local amusement park with his friends, and a mirror room su…