主题链接: pid=1005">huangjing 题意: 就是给了一个公式,然后求出第n项是多少... 思路: 题目中n的范围实在是太大,所以肯定直接递推肯定会超时,所以想到的是暴力打表,找循环节,可是也不是那么easy发现啊,所以这时候分析一下,由于最后都会mod7,所以总共同拥有7X7总情况,即A 0,1,2,3,4,5,6,7.B也是如此,所以循环节为49,这么这个问题就攻克了. .. 题目: Number Sequence Time Limit: 2000/1000 MS (Ja…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 198316    Accepted Submission(s): 49744 Problem Description A number sequence…

Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 86102 Accepted Submission(s): 20423 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n…

A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). InputThe input consists of multiple test cases. Each test case contains 3 integers A,…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 176080    Accepted Submission(s): 43527 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (…

f(n-1)和f(n-2)所有组合都49种子,这期可达49,但f(n-1)=f(n-2)=0如果是,列的总数目0.话题条件f(1)=f(2)=1.因此排除这样的情况.的最长期限48. #include<math.h> #include<stdio.h> #include<stdlib.h> #include<string.h> int main(void) { int a,b,n; int f[99]; while(scanf("%d%d%d&qu…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 187893    Accepted Submission(s): 46820 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 124827 Accepted Submission(s): 30331 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(…

HDU 1005 Number Sequence(数列) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) [Description] [题目描述] A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, an…

Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multiple test cases. Each test case…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 85249    Accepted Submission(s): 20209 Problem Description A number sequence…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 175657    Accepted Submission(s): 43409 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 154923    Accepted Submission(s): 37854 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

找规律,先找属于第几个循环,再找属于第几个数的第几位...... Number Sequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 31552 Accepted: 8963 Description A single positive integer i is given. Write a program to find the digit located in the position i in the sequ…

Number Sequence   A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multiple test cases. Each test case co…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 89984    Accepted Submission(s): 21437 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

Calculation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2272    Accepted Submission(s): 536 Problem Description Assume that f(0) = 1 and 0^0=1. f(n) = (n%10)^f(n/10) for all n bigger than ze…

题意: 给出两个数n,m,0<=n,m<=3000,输出n/m的循环小数表示以及循环节长度. 思路: 设立一个r[]数组记录循环小数,u[]记录每次的count,用于标记,小数计算可用 r[i]=n*10/m;n=n*10%10 直到n为0或u[n]!=0(找到循环节) 涉及到两个知识点:n/m的余数在0~m-1之间: 抽屉原理:循环次数最多不超过m+1次 具体见代码. //求循环节 #include<cstdio> #include<cstring> #define…

Period Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 14653   Accepted: 6965 Description For each prefix of a given string S with N characters (each character has an ASCII code between 97 and 126, inclusive), we want to know whether the…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 147964    Accepted Submission(s): 35964 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1005 主要内容: A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). 看到这样的公式很容易想到递归调用求解,但是在本题中n的取…

题目: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…

Problem Description A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multiple test cases. Each test case co…

1005 Number Sequence 时间限制: 1 Sec  内存限制: 60 MB 题目描述 A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).  输入 The input consists of multiple…

主要思路: 通过模拟除法运算过程,来判断循环节结束的位置,不断将余数*10再对除数取余得到新的余数,并记录下来,知道出现的余数之前出现过,此时小数开始循环. 例如: 假设   ->     a 是商  b是余数 (1/7) ->   (1)  a=1/7=0, b=1%7=; (2)  a=(b*10)/7=1  ,  b=(b*10)%7=3; (3)  a=(b*10)/7=4  ,  b=(b*10)%7=2; (4)  a=(b*10)/7=2  ,  b=(b*10)%7=6; (5…

HDU 1005 Number Sequence(数论) Problem Description: A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multipl…

http://acm.hdu.edu.cn/showproblem.php?pid=3746 Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4498    Accepted Submission(s): 2051 Problem Description CC always becomes very dep…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14416    Accepted Submission(s): 6016 Problem Description CC always becomes very depressed at the end of this month, he has checke…

Time Limit:1000MS     Memory Limit:32768KB Description ​A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A, B, and n, you are to calculate the value of f(n). Input The input consists of mult…

Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case co…