题目要求 Given a binary array, find the maximum number of consecutive 1s in this array. 题目分析及思路 给定一个01数组,要求找到这个数组中连续1的最大长度.可以考虑0的位置,结合数组切片,循环进行.要记得把最后数组的长度加上. python代码 class Solution: def findMaxConsecutiveOnes(self, nums: List[int]) -> int: if len(set(n…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/max-consecutive-ones/ Difficulty: Easy 题目描述 Given a binary array, find the maximum number of consecutive 1s in…

Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3. Note: T…

Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s.     The maximum number of consecutive 1s is 3. Not…

Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3. Note: T…

题目: Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3. Not…

题目描述 输入只有0和1的数组(长度为正整数,且<10000),找到最大的连续1的个数 比如[1,1,0,1,1,1],输出3 思路 遍历数组,统计当前连续个数curCount和最大连续值maxCount.If当前数组值为1,则curCount++:否则(值为0)比较curCount和maxCount,看是否需要替换,并把curCount置0 最后返回maxCount 错误:对于[1]这种边界条件没有考虑完全.这种时候上面的逻辑会输出0,而应该是1.也就是结束的时候需要增加一个比较,万一如果最后…

[LeetCode]659. Split Array into Consecutive Subsequences 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/split-array-into-consecutive-subsequences/description/ 题目描述: You are g…

problem 485. Max Consecutive Ones solution1: class Solution { public: int findMaxConsecutiveOnes(vector<int>& nums) { ; , max = INT_MIN; ; i<nums.size(); i++) { ) ans++; ) { if(max<ans) max = ans; ans = ; } } return max>ans ? max : ans;…

Question 485. Max Consecutive Ones Solution 题目大意:给一个数组,取连续1的最大长度 思路:遍历数组,连续1就加1,取最大 Java实现: public int findMaxConsecutiveOnes(int[] nums) { if (nums == null) return 0; int result = 0; int tmp = 0; for (int i : nums) { if (i == 1) { tmp++; } else { re…