Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements.    Your algorithm's time complexity must be…

Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…

A typical solution is heap based - "top K". Complexity is O(nlgk). typedef pair<int, unsigned> Rec; struct Comp { bool operator()(const Rec &r1, const Rec &r2) { return r1.second > r2.second; } }; class Solution { public: vector…

Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…

Top K Frequent Elements 347. Top K Frequent Elements [LeetCode] Top K Frequent Elements 前K个高频元素…

版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - Leetcode 347. Top K Frequent Elements - 题解 在线提交: https://leetcode.com/problems/top-k-frequent-elements/ Description Given a non-empty array of integers…

Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

[LeetCode]692. Top K Frequent Words 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/top-k-frequent-words/description/ 题目描述: Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency f…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: 347. Top K Frequent ElementsYou may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's…

［抄题］: 给一个单词列表,求出这个列表中出现频次最高的K个单词. ［思维问题］: 以为已经放进pq里就不能改了.其实可以改,利用每次取出的都是顶上的最小值就行了.(性质) 不知道怎么处理k个之外的数:先把peak, newpair拿出来 ［一句话思路］: ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 比较之前要新建对象.right.key.compareTo(left.key)是反的,而且需要单独写出来,因为比较的是k…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must be bet…

题目地址:https://leetcode.com/problems/top-k-frequent-elements/ 从一个数组中求解出现次数最多的k个元素,本质是top k问题,用堆排序解决. 关于堆排序,其时间复杂度在最好和最坏的场景下都是O(nlogn). 一开始想定义一个结构体,包含元素和元素个数两个成员,后直接用pair存储即可. 解题思路: 1. 分别统计每个数字的个数,建立数字和个数的映射,用pair存储,first=数字个数,second=数字,然后存入集合. 2. 以不同数字…

题目描述 题目链接 思路 由于要统计每个字符串的次数,以及字典序,所以,我们需要把用户每次add的字符串封装成一个对象,这个对象中包括了这个字符串和这个字符串出现的次数. 假设我们封装的对象如下: public class Word { public String value; // 对应的字符串 public int times; // 对应的字符串出现的次数 public Word(String v, int t) { value = v; times = t; } } topk的要求是:…

https://leetcode.com/problems/top-k-frequent-words/ Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the l…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 解题方法 字典 优先级队列 日期 题目地址:https://leetcode.com/problems/top-k-frequent-elements/description/ 题目描述 Given a non-empty array of integers, return the k most frequent elements. For example,…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. 其实最简单的就是想到就是用一个小顶堆实现,如果堆中元素个数小于K,则插入元素,如果大于K,则和堆顶比较,如果大于堆顶,则弹出堆顶,插入新元素. 自己实现红黑树有点难,好在C++ STL容器中,map,set和priority_queue都…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must be bet…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must be bet…

题目描述: Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must…

这个题的排序是用的PriorityQueue实现自动排列,优先队列用的是堆排序,堆排序请看:http://www.cnblogs.com/stAr-1/p/7569706.html 自定义了优先队列的排序方法,lambda表达式该复习下了... public List<String> topKFrequent(String[] words, int k) { /* 1.建立字符串和出现频率的映射 2.用优先队列PriorityQueue实现排序(相同频率用compareTo方法) 4.挑选出前…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…

Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…

Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…

Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…

思路: 堆.实现: #include <bits/stdc++.h> using namespace std; class Solution { public: inline bool cmp(pair<int, string> a, pair<int, string> b) { if (a.first > b.first) return true; if (a.first == b.first && a.second < b.second)…

给定一个非空的整数数组,返回其中出现频率前 k 高的元素.例如,给定数组 [1,1,1,2,2,3] , 和 k = 2,返回 [1,2].注意:    你可以假设给定的 k 总是合理的,1 ≤ k ≤ 数组中不相同的元素的个数.    你的算法的时间复杂度必须优于 O(n log n) , n 是数组的大小.详见:https://leetcode.com/problems/top-k-frequent-elements/description/C++: class Solution { pub…