The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…

[Leetcode/Javascript] 461.Hamming Distance 题目 The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note: 0 ≤ x, y < 231. Exampl…

package BitManipulation; //Question 461. Hamming Distance /* The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note: 0 ≤ x,…

题目描述 两个整数之间的汉明距离指的是这两个数字对应二进制位不同的位置的数目. 给出两个整数 x 和 y,计算它们之间的汉明距离. 注意: 0 ≤ x, y < 231. 示例: 输入: x = 1, y = 4 输出: 2 解释: 1 (0 0 0 1) 4 (0 1 0 0) ↑ ↑ 上面的箭头指出了对应二进制位不同的位置. 思路 思路一: 对两个数进行异或操作,位级表示不同的那一位为 1,统计有多少个 1 . 思路二: 使用 Integer.bitcount() 来统计 1 个的个数. 思…

problem 461. Hamming Distance solution1: 根据题意,所求汉明距离指的是两个数字的二进制对应位不同的个数.对应位异或操作为1的累积和. class Solution { public: int hammingDistance(int x, int y) { ; ; i<; i++) { <<i))^(y&(<<i))) ans++; } return ans; } }; solution2: 两个数字异或之后,统计结果二进制中1的…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 方法一:异或 + 字符串分割 方法二:异或 + 字符串遍历 方法三:异或 + 位统计 二刷 python解法 方法一:异或 + 字符串count 方法二:循环异或 方法三:异或 + 单次遍历 日期 题目地址: https://leetcode.com/problems/hamming-distance/ Total Accepted:…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Input: x = 1, y = 4 Output: 2 Explanation: 1   (0 0 0 1) 4   (0 1 0 0) ↑   ↑ 思路:就是求两数异或的二进制表示中有几个1. 如何求一个整数的二进制表示有几个一呢? while(x){x=x&(…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 2^31. Example: Input: x = 1, y = 4 Output: 2 Explanation:…