在一排座位( seats)中,1 代表有人坐在座位上,0 代表座位上是空的. 至少有一个空座位,且至少有一人坐在座位上. 亚历克斯希望坐在一个能够使他与离他最近的人之间的距离达到最大化的座位上. 返回他到离他最近的人的最大距离. 示例 1: 输入:[1,0,0,0,1,0,1] 输出:2 解释: 如果亚历克斯坐在第二个空位(seats[2])上,他到离他最近的人的距离为 2 . 如果亚历克斯坐在其它任何一个空位上,他到离他最近的人的距离为 1 . 因此,他到离他最近的人的最大距离是 2 . 示例…

In a row of seats, 1 represents a person sitting in that seat, and 0 represents that the seat is empty.  There is at least one empty seat, and at least one person sitting. Alex wants to sit in the seat such that the distance between him and the close…

problem 849. Maximize Distance to Closest Person solution1: class Solution { public: int maxDistToClosest(vector<int>& seats) { , n = seats.size(); vector<int> pos; ; i<n; ++i) { ) pos.push_back(i); } ; i<pos.size(); ++i) { ) res = m…

849. Maximize Distance to Closest Person 题目链接:https://leetcode.com/problems/maximize-distance-to-closest-person/description/ 思路:pre[i]存放i之前离最近的1的距离.post记录之后的. res = max(min(pre[i],[post[i])) 注意点:初始nst需要设计极大或极小值. 1 int maxDistToClosest(vector<int>&am…

In a row of seats, 1 represents a person sitting in that seat, and 0 represents that the seat is empty. There is at least one empty seat, and at least one person sitting. Alex wants to sit in the seat such that the distance between him and the closes…

In a row of seats, 1 represents a person sitting in that seat, and 0 represents that the seat is empty. There is at least one empty seat, and at least one person sitting. Alex wants to sit in the seat such that the distance between him and the closes…

In a row of seats, 1 represents a person sitting in that seat, and 0 represents that the seat is empty. There is at least one empty seat, and at least one person sitting. Alex wants to sit in the seat such that the distance between him and the closes…

In a row of seats, 1 represents a person sitting in that seat, and 0 represents that the seat is empty. There is at least one empty seat, and at least one person sitting. Alex wants to sit in the seat such that the distance between him and the closes…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3754 访问. 在一排座位( seats)中,1 代表有人坐在座位上,0 代表座位上是空的. 至少有一个空座位,且至少有一人坐在座位上. 亚历克斯希望坐在一个能够使他与离他最近的人之间的距离达到最大化的座位上. 返回他到离他最近的人的最大距离. 输入:[1,0,0,0,1,0,1] 输出:2 解释:如果亚历克斯坐在第二个空位(seats[2])上,他到离他最近的人…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/maximize-distance-to-closest-person/description/ 题目描述 In a row of seats, 1 represents a person sitting in that seat, and 0 represents that…

class Solution { public: int maxDistToClosest(vector<int>& seats) { ; ; for(int i:seats) //count the max length of continuous 0 { ) count++; else { maxseat=max(maxseat,count); count=; } } maxseat=(maxseat+)/; count=; ,j=seats.size()-; ) //count…

这是悦乐书的第328次更新,第351篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第198题(顺位题号是849).在一排座位中,1表示一个人坐在该座位上,0表示座位是空的.在这些座位中,至少有一个空座位,至少有一个人坐着.Alex想坐在座位上,以便他和离他最近的人之间的距离最远.返回距离最近的人的最大距离.例如: 输入:[1,0,0,0,1,0,1] 输出:2 说明:如果Alex坐在第二个空座位(seats[2]),那么离最近的人距离为2.如果Alex坐在任何其他空…

On a horizontal number line, we have gas stations at positions stations[0], stations[1], ..., stations[N-1], where N = stations.length. Now, we add K more gas stations so that D, the maximum distance between adjacent gas stations, is minimized. Retur…

On a horizontal number line, we have gas stations at positions stations[0], stations[1], ..., stations[N-1], where N = stations.length. Now, we add K more gas stations so that D, the maximum distance between adjacent gas stations, is minimized. Retur…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

In an exam room, there are N seats in a single row, numbered 0, 1, 2, ..., N-1. When a student enters the room, they must sit in the seat that maximizes the distance to the closest person.  If there are multiple such seats, they sit in the seat with…

最近开始刷LeetCode,准备按照专题来进行.所有的解题方案我都会放在GitHub上面,对于有价值的题目,我会重新在这里做记录,并且将解题方案贴出来,便于自己之后复习. Array 1. easy 122. Best Time to Buy and Sell Stock II 我的解题方案 官方解答 53. Maximum Subarray 我的解题方案 官方解答 849. Maximize Distance to Closest Person 我的解题方案 官方解答 532. K-diff…

Note: 后面数字n表明刷的第n + 1遍, 如果题目有**, 表明有待总结 Conclusion questions: [LeetCode] questions conclustion_BFS, DFS LeetCode questions conclustion_Path in Tree [LeetCode] questions conlusion_InOrder, PreOrder, PostOrder traversal [LeetCode] questions for Dynamic…

一.448. Find All Numbers Disappeared in an Array 给定一个范围在 1 ≤ a[i] ≤ n ( n = 数组大小 ) 的 整型数组,数组中的元素一些出现了两次,另一些只出现一次. 找到所有在 [1, n] 范围之间没有出现在数组中的数字. 您能在不使用额外空间且时间复杂度为O(n)的情况下完成这个任务吗? 你可以假定返回的数组不算在额外空间内. 输入:[4,3,2,7,8,2,3,1] 输出:[5,6] 1.算法思路(本题关键点:注意数组下标的范围和…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: IsOneBitCharacter * @Author: xiaof * @Description: TODO 717. 1-bit and 2-bit Characters * We have two special characters. The first charac…

数组篇 # 题名 刷题 通过率 难度 1 两数之和 C#LeetCode刷题之#1-两数之和(Two Sum) 43.1% 简单 4 两个排序数组的中位数 C#LeetCode刷题之#4-两个排序数组的中位数(Median of Two Sorted Arrays)-该题未达最优解 30.1% 困难 11 盛最多水的容器 C#LeetCode刷题之#11-盛最多水的容器(Container With Most Water) 37.9% 中等 15 三数之和 C#LeetCode刷题之#15-三数…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 把自己刷过的所有题目做一个整理,并且用简洁的语言概括了一下思路,汇总成了一个表格. 题目的排列顺序是按照先Easy再Medium再Hard排列的,暂时还没有把题目全部整理完成.后序我会把刷过的所有的题目都整理到这个文档里. 题目 难度 解法 题目地址 566. Reshape the Matrix Easy 变长数组,求余法,维护行列计算在新的数组中的位置 https://blog.c…

2015.3.23优化修改,现在已经能达到稳定60帧了.. 本博客地址:http://www.cnblogs.com/wolfred7464/ 创意来自于:http://ncase.me/sight-and-light/ 我要介绍的,就是这样的效果:(创意和素材都来自于上文的网址) 由于原文介绍的过于简练,导致像我这样的小白根本看不懂,所以我想要介绍的更易懂一点.. 一.画线段 在Cocos2d-x中,已经封装了通过Opengl ES的画线函数,只需要创建一个DrawNode对象,就可以画线了,…

Unity版本:5.6.2 控件Scroll View由4部分组成,如图: 1.含有Scroll Rect组件的根节点:Scroll View 2.含有Mask组件的节点:Viewport 3.所有内容的父节点Content,常含有布局控件 4.滚动条,包括横向和纵向 具体的节点细节使用可以参看官方文档:https://docs.unity3d.com/560/Documentation/Manual/script-ScrollRect.html 使用时遇到的问题记录: 1.显示区域怎么控制?节…

http://jiakaizhang.com/project/real-time-3d-reconstruction/ Real-time 3D Reconstruction using Kinect Real-time 3D Reconstruction Jiakai Zhang, Prof. Davi GeigerNew York UniversityJuly 2012 – September 2012 In order to reconstruct an indoor scene usin…

NGUI有一个UICenterOnChild脚本,可以轻松实现ScrollView中拖动子物体后保持一个子物体位于中心位置.然而UGUI就没这么方便了,官方并没有类似功能的脚本.网上找到一些运行效果都不对,可能因为UGUI需要配置的东西太多,RectTransfrom不同设置效果就不一样.故自己实现了该功能,使用时的配置如下: 1. 仅适用于水平方向拖动的ScrollRect.2. ScrollRect中的Grid必须使用GridLayoutGroup.3. 由于需要知道ScrollRect的宽…

@http://www-cs-faculty.stanford.edu/people/karpathy/cvpr2015papers/ CVPR 2015 papers (in nicer format than this) maintained by @karpathy NEW: This year I also embedded the (1,2-gram) tfidf vectors of all papers with t-sne and placed them in an interf…

本文实践了指纹识别生物特征识别研究论文A Fuzzy Vault Scheme的算法部分.原文请查看以下链接: Juels, A. & Sudan, M. Des Codes Crypt (2006) 38: 237. doi:10.1007/s10623-005-6343-z 准备知识: 1.有限域/伽罗华域(Galois Field,GF) 2.RS编码和纠错算法RS(Reed-Solomon)码 3.多项式构建和重构 4.模糊保险箱Fuzzy Vault 5.Talk is cheap,s…

滑动验证码介绍 本篇博客涉及到的验证码为滑动验证码,不同于极验证,本验证码难度略低,需要的将滑块拖动到矩形区域右侧即可完成. 这类验证码不常见了,官方介绍地址为:https://promotion.aliyun.com/ntms/act/captchaIntroAndDemo.html 使用起来肯定是非常安全的了,不是很好通过机器检测 如何判断验证码类型 这个验证码的标识一般比较明显,在页面源码中一般存在一个 nc.js 基本可以判定是阿里云的验证码了 <script type="text…