package addBinary67;/* Given two binary strings, return their sum (also a binary string).For example,a = "11"b = "1"Return "100". */public class Solution { public static String addBinary(String a, String b) { //ensure a.lengt…

题目: Given two binary strings, return their sum (also a binary string). (Easy) For example,a = "11"b = "1"Return "100". 分析: 思路很简单,就是按位依次相加,处理进位即可,循环条件里面可以写上carry == 1,用一个完整循环解决问题,而不用循环结束后再多加判定. 注意:题目给的是string,注意处理char和int转换. 代…

顺便把之前做过的一个简单难度的题也贴上来吧 67. Add Binary Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 这种问题 其实大多数人都做烂了 但是在实际应用中这个问题应用很广泛 有用二进制数基本就要处理加减乘除 一种最容易理解的方法但是不高效 那就是转为十进制处理后再转…

Given two binary strings, return their sum (also a binary string). Have you met this question in a real interview? Yes Example a = 11 b = 1 Return 100 LeetCode上的原题,请参见我之前的博客Add Binary. class Solution { public: /** * @param a a number * @param b a num…

Add Binary https://leetcode.com/problems/add-binary/ Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 算法 1) 假设aLen表示string a的长度,那么它的第aLen - 1个元素表示的最低位:string b同 2)…

1 题目 Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 接口 String addBinary(String a, String b) 2 思路 处理二进制求和和进位.从低位开始,一直相加并且维护进位.和Add Two Numbers的区别是这个题目低位在后面,所以要从strin…

67. Add Binary Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". public class Solution { public String addBinary(String a, String b) { String res =""; int l1…

这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…

Add Binary 本题收获: 对于相加而言,考虑进位以及进位之后的值为多少,全部进位完毕后进位还为1(11 + 11 = 110)需要添加一位.1.string中默认每个元素为char型 2.从int型转化为char型  s[i] - '0' 从char型转化为int型  s[i] + '0' 3.char型和int型相加时按上式会报错   s = (char)(s[i] + '0') +s s = (char)(s[i] + '0') +s 这样的写法 每次新的s(由(char)(s[i]…

Add BinaryGiven two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". SOLUTION: 指针指到两个字符串的末尾,不断往前推进,用carry表示进位.用stringbuilder来记录结果. 使用insert(0, c)函数将加出的结果不断插入到STRINGBUILDER. pub…