[CC-ANUCBC]Cards, bags and coins】的更多相关文章

题目大意 有n个数字,选出一个子集,有q个询问,求子集和模m等于0的方案数%1000000009.(n <= 100000,m <= 100,q <= 30) 假设数据很小,我们完全可以做一个背包. 我们沿着背包的思路,看能不能给物品分一下类,由于m比较小,完全按N个数字模M后的值进行分类,这样就变成了一个多重背包的问题.(转移时要乘上一个组合数) 这时候的时间复杂度是n*m,还是不能过. 对于DP时所枚举到的模m后余数j,它所进行的状态转移是一定的,如果把这些转移先预处理出来,时间复杂…
[CC-ANUCBC]Cards, bags and coins 题目大意: 给你\(n(n\le10^5)\)个数,\(q(q\le30)\)次询问,问从中选取若干个数使得这些数之和为\(m(m\le100)\)的方案数. 思路: 不难想到一个比较暴力的动态规划,用\(f[i][j]\)表示用了前\(i\)个数,和为\(j\)的方案数.时间复杂度\(\mathcal O(nmq)\). 发现动态规划中我们只关心每个数在模\(m\)意义下的值,因此直接用\(n\)个数转移实在是太愚蠢了. 将这些…
https://www.codechef.com/problems/ANUCBC n个数字,选出其一个子集.求有多少子集满足其中数字之和是m的倍数.n $\le$ 100000,m $\le$ 100,最多90组数据 傻逼题模数取什么1e9+9毁我一节课该死煞笔提 [15:13:47]刚刚心塞了一会儿出去跑了几步好点了,然后发现好像是生物老师在艺术楼走廊上给人讲题(今天好像有学校给成绩好的单独上课之类的活动,好多同学都来了艺术楼的一个教室了和机房隔一个拐角........) #include <…
D - Bags and Coins 思路:我们可以这样构造,最大的那个肯定是作为以一个树根,所以我们只要找到一个序列a1 + a2 + a3 .... + ak 并且ak为 所有点中最大的那个,那么我们a1, a2, a3..., ak-1 作为单独的点,其他没有涉及到的点套在ak的里面. 现在问题变成了找出a1, a2, a3, a4, ... , ak. 可以用bitset优化普通dp,因为要找路径,空间开不下,所以需要分段. #include<bits/stdc++.h> #defin…
题目链接 Yet another game from chef. Chef gives you N cards and M bags. Each of the N cards has an integer written on it. Now chef asks you to close your eyes and choose a subset of them. He then sums the numbers written on chosen cards, takes its absolu…
已知有n个包,和总共s个钱币. n,s<=70000. 每个包可以装钱币,还可以套别的包.每个包中的钱数等于 所有套的包的钱数 加上 自己装的钱. 所有的钱都在包内. 问给定每个包中的钱数,输出方案. 当方案不存在时,输出-1. ========== 乍一看好像是树,包就是结点,钱就是权值. 然后会发现可以转二叉树,即每个包,如果要套包,只套一个包. 然后就变成了简单的背包问题,求,给定n个包中各有ai枚钱币,求拿一些包使得总钱数等于s.…
颓!颓!颓!(bushi 前传: 贪心/构造/DP 杂题选做 贪心/构造/DP 杂题选做Ⅱ 51. CF758E Broken Tree 讲个笑话,这道题是 11.3 模拟赛的 T2,模拟赛里那道题的名字叫猛张(orz ztr),而我刚好在 11.4 把这题 A 了.乍一看好像也没啥问题,不过模拟赛时间是 2020.11.3,而我 AC 这道题的时间是 2021.11.4((( 首先看到这样的题我们肯定会想到贪心,具体来说我们 DFS 一遍整棵树,DFS 到一个节点 \(x\) 时,我们考虑用最…
http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1119 1119: Collecting Coins Time Limit: 3 Sec  Memory Limit: 128 MBSubmit: 144  Solved: 35[Submit][Status][Web Board] Description In a maze of r rows and c columns, your task is to collect as many coin…
The Fewest Coins Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6299   Accepted: 1922 Description Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the sm…
Cards Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 470    Accepted Submission(s): 72 Problem Description Given some cards each assigned a number, you're required to select EXACTLY K cards amo…
Description Karen just got home from the supermarket, and is getting ready to go to sleep. After taking a shower and changing into her pajamas, she looked at her shelf and saw an album. Curious, she opened it and saw a trading card collection. She re…
题目描述 Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins changes hands, i.e., the number of coins he uses to pay plus the number of coins he…
1068 Find More Coins (30 分)   Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special…
Atitti.dw cc 2015 绿色版本安装总结 1.1. 安装程序无法初始化.请下载adobe Support Advisor检测该问题.1 1.1.1. Adobe Application Manager无法安装解决办法1 1.2. Need  Adobe Application Manager??2 1.3. 启动的时候儿accept不能启动..冉green.bat运行给挂走ok兰..gujyi sh del oobe le ..zai run bat bg oobe install…
题目链接:Cards 听说这道题是染色问题的入门题,于是就去学了一下\(Bunside\)引理和\(P\acute{o}lya\)定理(其实还是没有懂),回来写这道题. 由于题目中保证"任意多次洗牌都可用这\(m\)种洗牌法中的一种代替",于是有了封闭性. 结合律显然成立. 题目中还保证了"对每种洗牌法,都存在一种洗牌法使得能回到原状态",逆元也有了. 只剩下一个单位元,我们手动补上.单位元就是不洗牌. 所以所有的洗牌方案构成了一个置换群.于是就可以用$Bunsid…
You have a total of n coins that you want to form in a staircase shape, where every k-th row must have exactly k coins. Given n, find the total number of full staircase rows that can be formed. n is a non-negative integer and fits within the range of…
 Gym 101047M Removing coins in Kem Kadrãn Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Practice Description standard input/output Andréh and his friend Andréas are board-game aficionados. They know many of their friend…
E. Vladik and cards time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Vladik was bored on his way home and decided to play the following game. He took n cards and put them in a row in front…
一.背景 公司的某一金融项目包含 12 个子系统,新需求一般按分支来开发,测完后合并到主干发布.开发团队需要同时维护开发环境.测试环境.模拟环境(主干).目前面临最大的两个问题: 1.子系统太多,每次发布(包括开发环境.测试环境.模拟环境)都比较耗时间 2.业务数据和报表的数据(主要是汇率.金额.手续费之类)仍依赖 Tester 人工验证,一个 sprint 一般需要走一周 以上. 自动化测试和持续集成提了近一年,但由于各种因素的影响,还是在原地踏步.所幸仍有一两个不怕背黑锅的搭档,今日终于迈出…
------------------------本文为自己实践所总结,概念性的东西不全,这里粗劣提下而已,网上很多,本文主要说下目前较流行的syn洪水攻击和cc攻击------------------------------------- 何为syn flood攻击: SYN Flood是一种广为人知的DoS(拒绝服务攻击)是DDoS(分布式拒绝服务攻击)的方式之一,这是一种利用TCP协议缺陷,发送大量伪造的TCP连接请求,从而使得被攻击方资源耗尽(CPU满负荷或内存不足)的攻击方式(TCP协议…
     源码编译,提示缺少gcc cc cl.exe 解决方案:       yum install -y gcc glibc…
传送门 Description Hasan and Bahosain want to buy a new video game, they want to share the expenses. Hasan has a set of N coins and Bahosain has a set of M coins. The video game costs W JDs. Find the number of ways in which they can pay exactly W JDs su…
1004: [HNOI2008]Cards Description 小春现在很清闲,面对书桌上的N张牌,他决定给每张染色,目前小春只有3种颜色:红色,蓝色,绿色.他询问Sun有 多少种染色方案,Sun很快就给出了答案.进一步,小春要求染出Sr张红色,Sb张蓝色,Sg张绝色.他又询问有多少种方 案,Sun想了一下,又给出了正确答案. 最后小春发明了M种不同的洗牌法,这里他又问Sun有多少种不同的染色方案. 两种染色方法相同当且仅当其中一种可以通过任意的洗牌法(即可以使用多种洗牌法,而每种方法可以使…
gcc 是GNU Compiler Collection,原名为Gun C语言编译器,因为它原本只能处理C语言,但gcc很快地扩展,包含很多编译器(C.C++.Objective-C.Ada.Fortran. Java),可以说gcc是GNU编译器集合. g++ 是C++编译器. cc 是 Unix系统的 C Compiler,一个是古老的 C 编译器.而 Linux 下 cc 一般是一个符号连接,指向 gcc:可以通过 $ ls -l /usr/bin/cc 来简单察看,该变量是 make 程…
基于CC写的插件,利用PCL中算法实现: void qLxPluginPCL::doRegionGrowing() { assert(m_app); if (!m_app) return; const ccHObject::Container& selectedEntities = m_app->getSelectedEntities(); size_t selNum = selectedEntities.size(); ) { m_app->dispToConsole("P…
包括两种计算方法:精确计算和近似计算(思考:local density=单位面积的点数 vs  local density =1/单个点所占的面积) 每种方法可以实现三种模式的点云密度计算,CC里面的点云计算依赖于 给定的近邻半径所对应的最佳八叉树层级 (通过findBestLevelForAGivenNeighbourhoodSizeExtraction()方法实现) 在GeometricalAnalysisTools类文件中实现. //volume of a unit sphere stat…
Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silverland dollar. One day Hibix opened purse and found there were some coins. He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact price(without chang…
转自:http://www.cnblogs.com/skynet/archive/2011/03/29/1998970.html 在项目开发时,有时候想知道源码文件中有多少后缀名为.cc..c..h的文件.下面介绍Linux几种方法统计后缀名为.cc..c..h的文件数的方法. 我以python3的源代码为例,python3的源码共有文件数: 这段时间在学习python3,我就把它作为例子啦.感慨下:Python3跟Python2比变化了好多!有兴趣的同学可以从代码库中checkout代码研究研…
C. Hongcow Buys a Deck of Cards time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output One day, Hongcow goes to the store and sees a brand new deck of n special cards. Each individual card is eit…
报错: Complete output from command /usr/bin/python -u -c "import setuptools, tokenize;__file__='/private/tmp/pip-build-kSfBfz/ujson/setup.py';f=getattr(tokenize, 'open', open)(__file__);code=f.read().replace('\r\n', '\n');f.close();exec(compile(code, _…