LeetCode题解 #8 String to Integer (atoi)】的更多相关文章

我现在在做一个叫<leetbook>的免费开源书项目,力求提供最易懂的中文思路,目前把解题思路都同步更新到gitbook上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ 008. String to Integer (atoi) [E] 题目 Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cas…
又是一道恶心的简单题. 一开始没想到这么多情况的,幸好LeetCode是个很人性化的oj,能让你知道你在哪个case上错了,否则一辈子都过不了. 考虑不周到只能一个个补了. 列举一下恶心的case //" 010" //" +004500" //" -0012a42" //"2147483648" //" b11228552307" //"18446744073709551617" //…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:字符串转整数,atoi,题解,Leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 代码 日期 题目地址:https://leetcode-cn.com/problems/string-to-integer-atoi/ 题目描述 Implement the myAtoi(string s) function, w…
一天一道LeetCode系列 (一)题目 Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for t…
Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…
题目: Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be…
题目描述: Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to…
虽然是easy,却是比较繁琐的一道题,需要考虑各种边界条件.在WA了好几遍之后,才把各种边界条件给补全.需要考虑到的因素如下: 输入不合法字符,非"0-9",对于首位,合法字符还包括"+"和"-"来代表正负号: 最前面允许出现很多个空格,即"      56": 当中间出现不合法字符,输出该不合法字符前面有效字符,如"+56a123",输出就是56: 注意越界的情况. 当注意了上述情况之后,就没有太大问题了…
1.  String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is inte…
题目String to Integer (atoi)(难度Medium) 大意是找出给定字串开头部分的整型数值,忽略开头的空格,注意符号,对超出Integer的数做取边界值处理. 方案1 class Solution { fun myAtoi(str: String): Int { val maxInt = " val maxIntS = "+2147483647" val minIntS = "-2147483648" val lengthMI = ma…