【leetcode 108 Convert Sorted Array to Binary Search Tree ----- java】的更多相关文章

leetcode 108 Convert Sorted Array to Binary Search Tree ----- java

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 给一个排好序的数组,然后求搜索二叉树 其实就是二分法,不难. /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNo…

37. leetcode 108. Convert Sorted Array to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 思路:利用一个有序数组构建一个平衡二叉排序树.直接递归构建,取中间的元素为根节点,然后分别构建左子树和右子树.…

[LeetCode] 108. Convert Sorted Array to Binary Search Tree ☆(升序数组转换成一个平衡二叉树)

108. Convert Sorted Array to Binary Search Tree 描述 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the…

LeetCode 108. Convert Sorted Array to Binary Search Tree （将有序数组转换成BST）

108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the tw…

leetcode 108. Convert Sorted Array to Binary Search Tree 、109. Convert Sorted List to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 这个题使用二分查找,主要要注意边界条件. 如果left > right,就返回NULL.每次更新的时候是mid-1,mid+1. 自己推一下基本就可以验证了. class Solution { public: TreeNode* sortedArrayToBST(vector<int>& nums) { ,nums.size() - ); } TreeNode* ToBST(vecto…

[LeetCode] 108. Convert Sorted Array to Binary Search Tree 把有序数组转成二叉搜索树

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…

LeetCode 108. Convert Sorted Array to Binary Search Tree （有序数组转化为二叉搜索树）

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题目标签:Tree 这道题目给了我们一个有序数组,从小到大.让我们把这个数组转化为height balanced BST. 首先来看一下什么是binary search tree: 每一个点的left < 节点 < right, 换一句话说,每一个点的值要大于左边的,小于右边的. 那么什么是heigh…

Java for LeetCode 108 Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 首先要理解,什么叫做height balanced BST Java for LeetCode 110 Balanced Binary Tree,然后就十分容易了,JAVA实现如下: public TreeNode sortedArrayToBST(int[] nums) { return…

LeetCode 108: Convert Sorted Array to Binary Search Tree DFS求解

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 1. 找到数组的中间节点将其置为根节点 2. 左边的即为左子树 3. 右边的即为右子树 4. 递归求解 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * Tr…

Leetcode#108 Convert Sorted Array to Binary Search Tree

原题地址 对于已排序数组,二分法递归构造BST 代码: TreeNode *buildBST(vector<int> &num, int i, int j) { if (i > j) return NULL; ; TreeNode *node = new TreeNode(num[m]); node->left = buildBST(num, i, m - ); node->right = buildBST(num, m + , j); return node; }…