Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 找出最大的相乘的数字,很简单,代码还可以优化的地方很多.但是速度还可以. publi…

题目链接:Maximum Product Subarray solutions同步在github 题目很简单,给一个数组,求一个连续的子数组,使得数组元素之积最大.这是求连续最大子序列和的加强版,我们可以先看看求连续最大子序列和的题目maximum-subarray,这题不难,我们举个例子. 假设数组[1, 2, -4, 5, -1, 10],前两个相加后得到3,更新最大值(为3),然后再加上-4后,和变成-1了,这时我们发现如果-1去加上5,不如舍弃前面相加的sum,5单独重新开始继续往后相加…

Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. Example 2: Input: [-2,0,-1]…

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 题目标签:Array, Dynamic Programming 题目给了我们一个nu…

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4], the contiguous subarray [2,3] has the largest product = 6. 解题思路: 计算连续的积最大,由于会有负数出现,因此需要用两个int表示包含num…

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 分析:这个题目就是让你求连续的子数组的乘积的最大值. (1)在数组中没有0的情况下,…

Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. Example 2: Input: [-2,0,-1]…

原题地址 简单动态规划,跟最大子串和类似. 一维状态空间可以经过压缩变成常数空间. 代码: int maxProduct(int A[], int n) { ) ; ]; ]; ]; ; i >= ; i--) { int tmp = minp; minp = min(A[i], min(A[i] * minp, A[i] * maxp)); maxp = max(A[i], max(A[i] * tmp, A[i] * maxp)); res = max(res, maxp); } retur…

Question 152. Maximum Product Subarray Solution 题目大意:求数列中连续子序列的最大连乘积 思路:动态规划实现,现在动态规划理解的还不透,照着公式往上套的,这个问题要注意正负,需要维护两个结果 Java实现: public int maxProduct(int[] nums) { if (nums.length == 1) return nums[0]; // 定义问题:状态及对状态的定义 // 设max[i]表示数列中第i项结尾的连续子序列的最大连…

53. Maximum Subarray 之前的值小于0就不加了.dp[i]表示以i结尾当前的最大和,所以需要用一个变量保存最大值. 动态规划的方法: class Solution { public: int maxSubArray(vector<int>& nums) { vector<int> dp(nums.size()); int res = INT_MIN; ;i < nums.size();i++){ dp[i] = nums[i]; &&…