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LeetCode Reverse Bits 反置位值

题意:给定一个无符号32位整数,将其二进制形式左右反置,再以整型返回. 思路:循环32轮,将n往右挤出一位就补到ans的尾巴上. class Solution { public: uint32_t reverseBits(uint32_t n) { ; uint32_t ans = ; int i; ; i<; i++ ) { ans <<= ; ) ans |= ; n >>=; } return ans; } }; Reverse Bits…

2016.5.16——leetcode:Reverse Bits（超详细讲解）

leetcode:Reverse Bits 本题目收获 移位(<<  >>), 或(|),与(&)计算的妙用 题目: Reverse bits of a given 32 bits unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in bin…

[LeetCode] Reverse Bits 翻转位

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If this function i…

[leetcode] Reverse Bits

Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up: If…

leetcode reverse bits python

Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If th…

[LeetCode] Reverse Bits 位操作

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If this function i…

lc面试准备:Reverse Bits

1 题目 Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If this funct…

LeetCode 190. Reverse Bits （反转位）

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). 题目标签: Bit Manipulation 这道题目…

LeetCode Reverse Linked List II 反置链表2

题意:将指定的一段位置[m,n]的链表反置,返回链表头. 思路:主要麻烦在链表头,如果要从链表头就开始,比较特殊. 目前用DFS实现,先找到m-1的位置,再找到n+1的位置,中间这段就是否要反置的,交给DFS解决,用个计数器来统计已经反置的个数即可. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(N…

LeetCode Reverse Nodes in k-Group 每k个节点为一组，反置链表

题意:给一个单链表,每k个节点就将这k个节点反置,若节点数不是k的倍数,则后面不够k个的这一小段链表不必反置. 思路:递归法.每次递归就将k个节点反置,将k个之后的链表头递归下去解决.利用原来的函数接口即可,不用重新定义. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; *…