problem 1170. Compare Strings by Frequency of the Smallest Character 参考 1. Leetcode_easy_1170. Compare Strings by Frequency of the Smallest Character; 完…

题目如下: Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c"and its frequency is 2. Now, giv…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双重循环 日期 题目地址:https://leetcode.com/problems/compare-strings-by-frequency-of-the-smallest-character/ 题目描述 Let's define a function f(s) over a non-empty string s, which calculates…

Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c" and its frequency is 2. Now, given st…

这是小川的第412次更新,第444篇原创 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第263题(顺位题号是1170).在一个非空字符串s上定义一个函数f(s),该函数计算s中最小字符的出现频率.例如,如果s ="dcce",则f(s)= 2,因为最小字符为"c",其频率为2. 现在,给定字符串数组queries和words,返回一个整数数组answer, 其中每个answer[i]是使得f(queries[i]) < f(W)的单词数量,其…

problem 859. Buddy Strings solution: class Solution { public: bool buddyStrings(string A, string B) { if(A.size()!=B.size()) return false; if(A==B && unordered_set<char>(A.begin(), A.end()).size()<A.size()) return true; vector<int>…

[LeetCode]165. Compare Version Numbers 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/compare-version-numbers/description/ 题目描述: Compare two version numbers version1 and vers…

[转]beyond compare 启动提示“应用程序发生错误”   今天到公司BCompare不能打开,重新安装也不能打开.最后处理下,就解决了.方法是把C:\Documents and Settings\[用户名]\Application Data\Scooter Software\Beyond Compare 3文件夹下的文件全部删除即可 WIN7下寻找:把C:\用户\[用户名]\AppData\Roaming\Scooter Software\Beyond Compare 3文件夹下的文…

Lukas Neuman--[ICDAR2015]Efficient Scene Text Localization and Recognition with Local Character Refinement 算法介绍 Fig. 2. Overview of the method. Initial text hypotheses efficiently generatedby a MSER detector are further refined using a local text mod…

problem 1071. Greatest Common Divisor of Strings solution class Solution { public: string gcdOfStrings(string str1, string str2) { return (str1+str2==str2+str1) ? (str1.substr(, gcd(str1.size(), str2.size()))) : ""; } }; 参考 1. Leetcode_easy_1071…

problem 893. Groups of Special-Equivalent Strings 题意: 感觉参考代码也是有点问题的... 参考 1. Leetcode_easy_893. Groups of Special-Equivalent Strings; 2. grandyang; 3. discuss; 完…

problem 844. Backspace String Compare solution1: class Solution { public: bool backspaceCompare(string S, string T) { return backspace(S)==backspace(T); } string backspace(string str) { string res =""; for(auto ch:str) { if(ch=='#') { if(!res.em…

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

原文网址:http://mt.sohu.com/20160329/n442685522.shtml Beyond Compare想必大家都知道,它是一个专业级的一个文件对比工具,由于工作原因,我们会经常用到它.旧版的Beyond Compare只能应用于Windows和Linux系统,使得成千上万的果粉望洋兴叹,现在最新版Beyond Compare4已经全面支持Mac系统,而且Beyond Compare官方为了方便果粉们的使用,已经正式发布Beyond Comparefor Mac中文版.…

题目: Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characte…

在beyond compare的5~6年的使用过程中突然有一天发现,beyond compare对比的文件都一样,但是却都显示红色!很是烦人. 这是因为beyond compare一开始对比的时时间,时间不同,显示的就是有差异的. 解决这个问题有2个方法(发放一不行再试下方法二) 方法一. 我们只要在菜单Session-Session Settings...把对比规则改为“2进制对比”就可以解决这个问题.  方法二. 方法一不管用的话,我们只要在菜单Session-Session Setting…

problem 415. Add Strings solution: class Solution { public: string addStrings(string num1, string num2) { ; ; ; string res = ""; || j>= || carry) { )?:(num1[i--]-)?:(num2[j--]-')) + carry;//注意运算符的优先级顺序. carry = tmp/; res = to_string(tmp%) + r…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 将乘积逐位逆序存放在int数组result中. 记num1当前为第i位,num2当前为第j位,则乘积存放在result[(n1-1-i)+(n2-1-j…

Gene and Gina have a particular kind of farm. Instead of growing animals and vegetables, as it is usually the case in regular farms, they grow strings. A string is a sequence of characters. Strings have the particularity that, as they grow, they add…

Given a string s, sort it in decreasing order based on the frequency of the characters. The frequency of a character is the number of times it appears in the string. Return the sorted string. If there are multiple answers, return any of them. 考察了map的…

Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Note: You must not use any built-in BigInteger library or convert the inputs to integer directly. 暴力法 转换为数值型变量再进行…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典保存位置 字典保存映射 日期 题目地址:https://leetcode.com/problems/isomorphic-strings/#/description 题目描述 Given two strings s and t, determine if they are isomorphic. Two strings are isomorphi…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 优先级队列 排序 日期 题目地址:https://leetcode.com/problems/sort-characters-by-frequency/description/ 题目描述 Given a string, sort it in decreasing order based on the frequency of character…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 日期 题目地址:https://leetcode.com/problems/buddy-strings/description/ 题目描述 Given two strings A and B of lowercase letters, return true if and only if we can swap two letters in A…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/multiply-strings/description/ 题目描述 Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and nu…

http://poj.org/problem?id=2406 题意:给定一个字符串 L,已知这个字符串是由某个字符串 S 重复 R 次而得到的,求 R 的最大值.(长度<=1000000) #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <iostream> using namespace std; int p[20000…

problem 1021. Remove Outermost Parentheses 参考 1. Leetcode_easy_1021. Remove Outermost Parentheses; 完…

problem 1022. Sum of Root To Leaf Binary Numbers 参考 1. Leetcode_easy_1022. Sum of Root To Leaf Binary Numbers; 完…

problem 1025. Divisor Game 参考 1. Leetcode_easy_1025. Divisor Game; 完…

problem 1029. Two City Scheduling 参考 1. Leetcode_easy_1029. Two City Scheduling; 完…