题目 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Credits: Special thanks t…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 这一题可以用排序之后查看序列正中间那个元素的方法来解.但…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路: 找到一个数组中出现次数超过一半的数.排序.哈希等…

Problem Introduction An element of a sequence of length \(n\) is called a majority element if it appears in the sequence strictly more than \(n/2\) times. Problem Description Task.The goal in this code problem is to check whether an input sequence co…

这是悦乐书的第181次更新,第183篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第40题(顺位题号是169).给定大小为n的数组,找到数组中出现次数超过n/2的元素.假设该数组非空,并且该元素始终存在于数组中.例如: 输入:[3,2,3] 输出:3 输入:[2,2,1,1,1,2,2] 输出:2 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java语言编写和测试. 02 第一种解法 我们可以先将数组排序,然后使…

problem: Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 将一个数组里的和给定元素相同的元素删除,在该数组里操作,返回剩下的个数.注意,数组的前部分要保留…

package y2019.Algorithm.array; import java.util.HashMap; import java.util.Map; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: MajorityElement * @Author: xiaof * @Description: 169. Majority Element * Given an array of…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 思路: [LeetCode 169]Majority Element 的拓展,这回要求的是出现次数超过三分之一次的数字咯,动动我们的大脑思考下,这样的数最多会存在几个呢,当然是2个嘛.因此,接着上一题的方…

Leetcode之分治法专题-169. 求众数(Majority Element) 给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素. 你可以假设数组是非空的,并且给定的数组总是存在众数. 示例 1: 输入: [3,2,3] 输出: 3 示例 2: 输入: [2,2,1,1,1,2,2] 输出: 2 分治法,顾名思义,分而治之,就是把要求解的问题,一分为二,在每个分支上再求解. 这题里,我们可以求出一个mid=(L+R)>>>1;求mid的…

169. Majority Element /** * @param {number[]} nums * @return {number} */ var majorityElement = function(nums) { var hash = {}; var y=-1,z; //注意这里的方括号,利用变量访问对象属性时要用方括号 for(var i=0;i<=nums.length-1;i++){ if(hash[nums[i]]){ hash[nums[i]]++; }else{ hash[…