Wiggle Sort: 注意:解法一是每次i增加2,题目不是保证3个3个的情况,而是整个数组都要满足要求. 解法一错误版本: 如果nums的长度是4,这种情况下nums[i+1]会越界.但是如果你用的是i和i-1的组合,一定可以不会越界,因为i不越界i-1就一定不会越界,for循环控制i,i越界了整个循环就结束了. class Solution { public: void wiggleSort(vector<int>& nums) { sort(nums.begin(),nums.…

Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 题目标签:Array, Sort 题目给了我们一个nums array, 让我们wiggle sort.…

Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 给一个没有排序的数组,将其重新排序成nums[0] <= nums[1] >= nums[2…

Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 观察wiggle sort之后的结果可知: nums[even] <= nums[even+1]…

Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. Solution: Loop through, when odd index num should be…

Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Example 1: Input: nums = [1, 5, 1, 1, 6, 4] Output: One possible answer is [1, 4, 1, 5, 1, 6]. Example 2: Input: nums = [1, 3, 2, 2, 3, 1] Output: One po…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 排序后交换相邻元素 日期 题目地址:https://leetcode-cn.com/problems/wiggle-sort/ 题目描述 Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3]....…

原题 Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 解析 摇摆排序 只要奇数位上的数比左右偶数位上的数都大即可 思路 贪心算法:在对问题求解时,总是做…

题目: Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 链接: http://leetcode.com/problems/wiggle-sort/ 题解…

利用中位数的概念,中位数就是将一组数分成2等份(若为奇数,则中位数既不属于左也不属于右,所以是2等份),其一组数中任何一个元素都大于等于另一组数 那么我们是不是只要一左一右配合着插入,就保证了差值+-+-+-的要求? 由于题目输入限制了,必定存在解,所以此处我们不需要担心如果重复中位数太多,出现一左一右相等的情况 算法步骤: 1)找到中位数 利用lc215 Kth Largest...,将k=(nums.length+1) / 2,可以在o(n)内求出中位数 2)一左一右插入 0 2 4 ..…

Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 这道题让我们求摆动排序,跟Wiggle Sort II相比起来,这道题的条件宽松很多,只因为多了一个等号…

Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Example:(1) Given nums = [1, 5, 1, 1, 6, 4], one possible answer is [1, 4, 1, 5, 1, 6]. (2) Given nums = [1, 3, 2, 2, 3, 1], one possible answer is [2, 3…

Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Example 1: Input: nums = [1, 5, 1, 1, 6, 4] Output: One possible answer is [1, 4, 1, 5, 1, 6]. Example 2: Input: nums = [1, 3, 2, 2, 3, 1] Output: One po…

一. 题目描写叙述 Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3]- For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 二. 题目分析 题目给出一个未排序的数组,调整元素的大小使其满足nums[0] <=…

链接:https://leetcode.com/tag/sort/ [56]Merge Intervals (2019年1月26日,谷歌tag复习) 合并区间 Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. 题解:先按照interval的begin从小到大s…

Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Notice You may assume all input has valid answer. ExampleGiven nums = [1, 5, 1, 1, 6, 4], one possible answer is [1, 4, 1, 5, 1, 6]. Given nums = [1, 3,…

Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... Notice Please complete the problem in-place. ExampleGiven nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. LeetCode上的原题,…

Wiggle Sort II Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... 注意事项 You may assume all input has valid answer. 样例 Given nums = [1, 5, 1, 1, 6, 4], one possible answer is [1, 4, 1, 5, 1, 6]. Given nums…

Wiggle Sort Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... 注意事项 Please complete the problem in-place. 样例 Given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 解题 竟然可以…

Wiggle Sort Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 分析: 序列单调性问题,本题要求在不开额外数组的情况下使得序列呈现增减增减的规律…

LeetCode 15 3Sum [sort] <c++> 给出一个一维数组,找出其中所有和为零的三元组(元素集相同的视作同一个三元组)的集合. C++ 先自己写了一发,虽然过了,但跑了308 ms... 我的做法是先排序,扫一遍,处理出unorder_map<0-a[i],i>的hash表.再\(O(n^2)\)枚举前两个元素,查表直接知道第三个元素的位置,然后将三元组加入到答案集合中,通过枚举时添加的限制条件规避重复元素. 复杂度\(O(n^2)\),由于使用了hash表,常数…

Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... Notice Please complete the problem in-place. Example Given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 分析: 排序,从第三个开…

LintCode 508: Wiggle Sort 题目描述 给你一个没有排序的数组,请将原数组就地重新排列满足如下性质 nums[0] <= nums[1] >= nums[2] <= nums[3].... Thu Feb 23 2017 思路 这道题看起来好像无从下手,但其实思路很简单,方法也有很多种. 第一种方法 先将数组排序,然后将第二个.第三个数交换,第四个.第五个数交换...即可.时间复杂度是\(O(nlogn)\). 第二种方法 第二种方法先找出数字们的中位数,然后将大于…

题目如下: 解题思路:本题和[leetcode]75. Sort Colors类似,但是没有要求在输入数组本身修改,所以难度降低了.引入一个新的数组,然后遍历输入数组,如果数组元素是是偶数,插入到新数组头部,否则追加到尾部. 代码如下: class Solution(object): def sortArrayByParity(self, A): """ :type A: List[int] :rtype: List[int] """ res =…

Problem Description: Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. The final sorted nums needs to…

Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Example:(1) Given nums = [1, 5, 1, 1, 6, 4], one possible answer is [1, 4, 1, 5, 1, 6]. (2) Given nums = [1, 3, 2, 2, 3, 1], one possible answer is [2, 3…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white a…

Insertion Sort List 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/insertion-sort-list/description/ Description Sort a linked list using insertion sort. Solution class Solution { private: void insert(ListNode* &head, int x) { if (head == NULL) { hea…

给定一个无序的数组nums,将它重新排列成nums[0] < nums[1] > nums[2] < nums[3]...的顺序.例子:(1) 给定nums = [1, 5, 1, 1, 6, 4],一个可能的结果是[1, 4, 1, 5, 1, 6].(2) 给定nums = [1, 3, 2, 2, 3, 1],一个可能的结果是[2, 3, 1, 3, 1, 2].注意:你可以假设所有输入都有有效的结果.进阶:你能用 O(n) 时间复杂度 / 或原地 O(1) 额外空间来实现吗? 详…

Sort a linked list using insertion sort. A graphical example of insertion sort. The partial sorted list (black) initially contains only the first element in the list.With each iteration one element (red) is removed from the input data and inserted in…